HTML Diff
0 added 0 removed
Original 2026-01-01
Modified 2026-02-28
1 <p>The<a>long division</a>method is particularly used for non-perfect square numbers. In this method, we should check the closest perfect square number for the given number. Let us now learn how to find the<a>square root</a>using the long division method, step by step.</p>
1 <p>The<a>long division</a>method is particularly used for non-perfect square numbers. In this method, we should check the closest perfect square number for the given number. Let us now learn how to find the<a>square root</a>using the long division method, step by step.</p>
2 <p><strong>Step 1:</strong>To begin, we need to group the numbers from right to left. In the case of 493, we consider 93 and 4.</p>
2 <p><strong>Step 1:</strong>To begin, we need to group the numbers from right to left. In the case of 493, we consider 93 and 4.</p>
3 <p><strong>Step 2:</strong>Now we need to find n whose square is<a>less than</a>or equal to 4. We can say n is 2 because 2 x 2 = 4. Now the<a>quotient</a>is 2, and after subtracting 4, the<a>remainder</a>is 0.</p>
3 <p><strong>Step 2:</strong>Now we need to find n whose square is<a>less than</a>or equal to 4. We can say n is 2 because 2 x 2 = 4. Now the<a>quotient</a>is 2, and after subtracting 4, the<a>remainder</a>is 0.</p>
4 <p><strong>Step 3:</strong>Bring down 93, which is the new<a>dividend</a>. Add the old<a>divisor</a>with the same number (2), and we get 4, which will be our new divisor.</p>
4 <p><strong>Step 3:</strong>Bring down 93, which is the new<a>dividend</a>. Add the old<a>divisor</a>with the same number (2), and we get 4, which will be our new divisor.</p>
5 <p><strong>Step 4:</strong>The new divisor will be the sum of the previous divisor and quotient. We need to find n such that 4n x n ≤ 93.</p>
5 <p><strong>Step 4:</strong>The new divisor will be the sum of the previous divisor and quotient. We need to find n such that 4n x n ≤ 93.</p>
6 <p><strong>Step 5:</strong>Consider n as 2, then 42 x 2 = 84.</p>
6 <p><strong>Step 5:</strong>Consider n as 2, then 42 x 2 = 84.</p>
7 <p><strong>Step 6:</strong>Subtract 84 from 93, the difference is 9, and the quotient is 22.</p>
7 <p><strong>Step 6:</strong>Subtract 84 from 93, the difference is 9, and the quotient is 22.</p>
8 <p><strong>Step 7:</strong>Since the dividend is less than the divisor, we need to add a decimal point. Adding the decimal point allows us to add two zeroes to the dividend. Now the new dividend is 900.</p>
8 <p><strong>Step 7:</strong>Since the dividend is less than the divisor, we need to add a decimal point. Adding the decimal point allows us to add two zeroes to the dividend. Now the new dividend is 900.</p>
9 <p><strong>Step 8:</strong>Find the new divisor, which is 445 because 445 x 2 = 890.</p>
9 <p><strong>Step 8:</strong>Find the new divisor, which is 445 because 445 x 2 = 890.</p>
10 <p><strong>Step 9:</strong>Subtracting 890 from 900, we get the result 10.</p>
10 <p><strong>Step 9:</strong>Subtracting 890 from 900, we get the result 10.</p>
11 <p><strong>Step 10:</strong>Now the quotient is 22.2.</p>
11 <p><strong>Step 10:</strong>Now the quotient is 22.2.</p>
12 <p><strong>Step 11:</strong>Continue these steps until we get two numbers after the decimal point. Suppose if there are no decimal values, continue till the remainder is zero.</p>
12 <p><strong>Step 11:</strong>Continue these steps until we get two numbers after the decimal point. Suppose if there are no decimal values, continue till the remainder is zero.</p>
13 <p>So the square root of √493 is approximately 22.205.</p>
13 <p>So the square root of √493 is approximately 22.205.</p>
14  
14