HTML Diff
0 added 0 removed
Original 2026-01-01
Modified 2026-02-28
1 <p>The<a>long division</a>method is particularly used for non-perfect square numbers. In this method, we should check the closest perfect square number for the given number. Let us now learn how to find the<a>square root</a>using the long division method, step by step.</p>
1 <p>The<a>long division</a>method is particularly used for non-perfect square numbers. In this method, we should check the closest perfect square number for the given number. Let us now learn how to find the<a>square root</a>using the long division method, step by step.</p>
2 <p><strong>Step 1:</strong>To begin with, we need to group the numbers from right to left. In the case of 6100, we need to group it as 00 and 61.</p>
2 <p><strong>Step 1:</strong>To begin with, we need to group the numbers from right to left. In the case of 6100, we need to group it as 00 and 61.</p>
3 <p><strong>Step 2:</strong>Now we need to find n whose square is<a>less than</a>or equal to 61. We can take n as 7 because 7 x 7 = 49, which is lesser than 61. Now the<a>quotient</a>is 7, and after subtracting 49 from 61, the<a>remainder</a>is 12.</p>
3 <p><strong>Step 2:</strong>Now we need to find n whose square is<a>less than</a>or equal to 61. We can take n as 7 because 7 x 7 = 49, which is lesser than 61. Now the<a>quotient</a>is 7, and after subtracting 49 from 61, the<a>remainder</a>is 12.</p>
4 <p><strong>Step 3:</strong>Now let us bring down 00, making the new<a>dividend</a>1200. Add the old<a>divisor</a>with the same number, 7 + 7, to get 14, which will be our new divisor.</p>
4 <p><strong>Step 3:</strong>Now let us bring down 00, making the new<a>dividend</a>1200. Add the old<a>divisor</a>with the same number, 7 + 7, to get 14, which will be our new divisor.</p>
5 <p><strong>Step 4:</strong>The new divisor will be the sum of the dividend and quotient. Now we get 14n as the new divisor, and we need to find the value of n.</p>
5 <p><strong>Step 4:</strong>The new divisor will be the sum of the dividend and quotient. Now we get 14n as the new divisor, and we need to find the value of n.</p>
6 <p><strong>Step 5:</strong>The next step is finding 14n × n ≤ 1200. Let us consider n as 8, now 148 x 8 = 1184.</p>
6 <p><strong>Step 5:</strong>The next step is finding 14n × n ≤ 1200. Let us consider n as 8, now 148 x 8 = 1184.</p>
7 <p><strong>Step 6:</strong>Subtract 1184 from 1200, the difference is 16, and the quotient becomes 78.</p>
7 <p><strong>Step 6:</strong>Subtract 1184 from 1200, the difference is 16, and the quotient becomes 78.</p>
8 <p><strong>Step 7:</strong>Since the dividend is less than the divisor, we need to add a decimal point. Adding the decimal point allows us to add two zeroes to the dividend. Now the new dividend is 1600.</p>
8 <p><strong>Step 7:</strong>Since the dividend is less than the divisor, we need to add a decimal point. Adding the decimal point allows us to add two zeroes to the dividend. Now the new dividend is 1600.</p>
9 <p><strong>Step 8:</strong>Now we need to find the new divisor that is 781 because 781 x 2 = 1562.</p>
9 <p><strong>Step 8:</strong>Now we need to find the new divisor that is 781 because 781 x 2 = 1562.</p>
10 <p><strong>Step 9:</strong>Subtracting 1562 from 1600, we get the result 38.</p>
10 <p><strong>Step 9:</strong>Subtracting 1562 from 1600, we get the result 38.</p>
11 <p><strong>Step 10:</strong>Now the quotient is 78.1.</p>
11 <p><strong>Step 10:</strong>Now the quotient is 78.1.</p>
12 <p><strong>Step 11:</strong>Continue doing these steps until we get two numbers after the decimal point. Suppose if there are no decimal values, continue till the remainder is zero.</p>
12 <p><strong>Step 11:</strong>Continue doing these steps until we get two numbers after the decimal point. Suppose if there are no decimal values, continue till the remainder is zero.</p>
13 <p>So the square root of √6100 is approximately 78.10.</p>
13 <p>So the square root of √6100 is approximately 78.10.</p>
14  
14