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Original
2026-01-01
Modified
2026-02-28
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<p>The<a>long division</a>method is particularly used for non-perfect square numbers. In this method, we should check the closest perfect square number for the given number. Let us now learn how to find the<a>square root</a>using the long division method, step by step.</p>
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<p>The<a>long division</a>method is particularly used for non-perfect square numbers. In this method, we should check the closest perfect square number for the given number. Let us now learn how to find the<a>square root</a>using the long division method, step by step.</p>
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<p><strong>Step 1:</strong>To begin with, we need to group the numbers from right to left. In the case of 1515, we need to group it as 15 and 15.</p>
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<p><strong>Step 1:</strong>To begin with, we need to group the numbers from right to left. In the case of 1515, we need to group it as 15 and 15.</p>
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<p><strong>Step 2:</strong>Now we need to find n whose square is<a>less than</a>or equal to the first group, which is 15. We can say n as ‘3’ because 3 × 3 = 9 is less than 15. Now the<a>quotient</a>is 3, after subtracting 9 from 15, the<a>remainder</a>is 6.</p>
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<p><strong>Step 2:</strong>Now we need to find n whose square is<a>less than</a>or equal to the first group, which is 15. We can say n as ‘3’ because 3 × 3 = 9 is less than 15. Now the<a>quotient</a>is 3, after subtracting 9 from 15, the<a>remainder</a>is 6.</p>
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<p><strong>Step 3:</strong>Now let us bring down the next group, which is 15, making the new<a>dividend</a>615. Add the old<a>divisor</a>with the same number 3 + 3 = 6, which will be our new divisor.</p>
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<p><strong>Step 3:</strong>Now let us bring down the next group, which is 15, making the new<a>dividend</a>615. Add the old<a>divisor</a>with the same number 3 + 3 = 6, which will be our new divisor.</p>
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<p><strong>Step 4:</strong>The new divisor will be 60n, where n is our next digit in the quotient.</p>
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<p><strong>Step 4:</strong>The new divisor will be 60n, where n is our next digit in the quotient.</p>
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<p><strong>Step 5:</strong>Find n such that 60n × n ≤ 615. Let us consider n as 1. Now 601 × 1 = 601.</p>
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<p><strong>Step 5:</strong>Find n such that 60n × n ≤ 615. Let us consider n as 1. Now 601 × 1 = 601.</p>
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<p><strong>Step 6:</strong>Subtract 601 from 615, the remainder is 14, and update the quotient to 31.</p>
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<p><strong>Step 6:</strong>Subtract 601 from 615, the remainder is 14, and update the quotient to 31.</p>
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<p><strong>Step 7:</strong>Since the dividend is less than the divisor, add a decimal point. Adding the decimal point allows us to add two zeroes to the dividend, making it 1400.</p>
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<p><strong>Step 7:</strong>Since the dividend is less than the divisor, add a decimal point. Adding the decimal point allows us to add two zeroes to the dividend, making it 1400.</p>
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<p><strong>Step 8:</strong>Now find the new divisor, which is 620, because 6202 × 2 = 1240.</p>
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<p><strong>Step 8:</strong>Now find the new divisor, which is 620, because 6202 × 2 = 1240.</p>
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<p><strong>Step 9:</strong>Subtracting 1240 from 1400 gives 160.</p>
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<p><strong>Step 9:</strong>Subtracting 1240 from 1400 gives 160.</p>
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<p><strong>Step 10:</strong>The quotient is now 38.92.</p>
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<p><strong>Step 10:</strong>The quotient is now 38.92.</p>
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<p><strong>Step 11:</strong>Continue these steps until you get the desired precision.</p>
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<p><strong>Step 11:</strong>Continue these steps until you get the desired precision.</p>
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<p>So the square root of √1515 ≈ 38.923.</p>
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<p>So the square root of √1515 ≈ 38.923.</p>
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