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Original
2026-01-01
Modified
2026-02-28
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<p>The long<a>division</a>method is particularly used for non-perfect square numbers. In this method, we should check the closest perfect square number for the given number. Let us now learn how to find the<a>square root</a>using the long division method, step by step.</p>
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<p>The long<a>division</a>method is particularly used for non-perfect square numbers. In this method, we should check the closest perfect square number for the given number. Let us now learn how to find the<a>square root</a>using the long division method, step by step.</p>
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<p><strong>Step 1:</strong>To begin with, we need to group the numbers from right to left. In the case of 263, we need to group it as 63 and 2.</p>
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<p><strong>Step 1:</strong>To begin with, we need to group the numbers from right to left. In the case of 263, we need to group it as 63 and 2.</p>
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<p><strong>Step 2:</strong>Now we need to find n whose square is<a>less than</a>or equal to 2. We can say n as ‘1’ because 1 × 1 is less than or equal to 2. Now the<a>quotient</a>is 1, and after subtracting 1 from 2, the<a>remainder</a>is 1.</p>
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<p><strong>Step 2:</strong>Now we need to find n whose square is<a>less than</a>or equal to 2. We can say n as ‘1’ because 1 × 1 is less than or equal to 2. Now the<a>quotient</a>is 1, and after subtracting 1 from 2, the<a>remainder</a>is 1.</p>
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<p><strong>Step 3:</strong>Now let us bring down 63, making the new<a>dividend</a>163. Add the old<a>divisor</a>with the same number 1 + 1, we get 2, which will be our new divisor.</p>
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<p><strong>Step 3:</strong>Now let us bring down 63, making the new<a>dividend</a>163. Add the old<a>divisor</a>with the same number 1 + 1, we get 2, which will be our new divisor.</p>
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<p><strong>Step 4:</strong>We need to find the new digit of the divisor such that 2n × n ≤ 163. Let us consider n as 6. Now 26 × 6 = 156.</p>
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<p><strong>Step 4:</strong>We need to find the new digit of the divisor such that 2n × n ≤ 163. Let us consider n as 6. Now 26 × 6 = 156.</p>
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<p><strong>Step 5:</strong>Subtract 156 from 163, the difference is 7, and the quotient is 16.</p>
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<p><strong>Step 5:</strong>Subtract 156 from 163, the difference is 7, and the quotient is 16.</p>
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<p><strong>Step 6:</strong>Since the dividend is less than the divisor, we need to add a decimal point. Adding the decimal point allows us to add two zeroes to the dividend. Now the new dividend is 700.</p>
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<p><strong>Step 6:</strong>Since the dividend is less than the divisor, we need to add a decimal point. Adding the decimal point allows us to add two zeroes to the dividend. Now the new dividend is 700.</p>
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<p><strong>Step 7:</strong>Now we need to find the new divisor, which is 162. Multiply 162 × 4 = 648.</p>
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<p><strong>Step 7:</strong>Now we need to find the new divisor, which is 162. Multiply 162 × 4 = 648.</p>
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<p><strong>Step 8:</strong>Subtracting 648 from 700 we get the result 52.</p>
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<p><strong>Step 8:</strong>Subtracting 648 from 700 we get the result 52.</p>
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<p><strong>Step 9:</strong>Continue doing these steps until we get two numbers after the decimal point. Suppose if there are no decimal values, continue until the remainder is zero.</p>
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<p><strong>Step 9:</strong>Continue doing these steps until we get two numbers after the decimal point. Suppose if there are no decimal values, continue until the remainder is zero.</p>
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<p>So the square root of √263 ≈ 16.217.</p>
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<p>So the square root of √263 ≈ 16.217.</p>
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