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Original
2026-01-01
Modified
2026-02-28
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<p>The long<a>division</a>method is particularly used for non-perfect square numbers. In this method, we should check the closest perfect square number for the given number. Let us now learn how to find the<a>square root</a>using the long division method, step by step.</p>
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<p>The long<a>division</a>method is particularly used for non-perfect square numbers. In this method, we should check the closest perfect square number for the given number. Let us now learn how to find the<a>square root</a>using the long division method, step by step.</p>
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<p><strong>Step 1:</strong>To begin with, we need to group the numbers from right to left. In the case of 1525, we need to group it as 15 and 25.</p>
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<p><strong>Step 1:</strong>To begin with, we need to group the numbers from right to left. In the case of 1525, we need to group it as 15 and 25.</p>
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<p><strong>Step 2:</strong>Now we need to find n whose square is 15. We can say n as ‘3’ because 3 x 3 = 9 is<a>less than</a>15. Now the<a>quotient</a>is 3 after subtracting 9 from 15, the<a>remainder</a>is 6.</p>
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<p><strong>Step 2:</strong>Now we need to find n whose square is 15. We can say n as ‘3’ because 3 x 3 = 9 is<a>less than</a>15. Now the<a>quotient</a>is 3 after subtracting 9 from 15, the<a>remainder</a>is 6.</p>
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<p><strong>Step 3:</strong>Now let us bring down 25, making the new<a>dividend</a>625. Add the old<a>divisor</a>with the same number: 3 + 3, we get 6, which will be our new divisor.</p>
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<p><strong>Step 3:</strong>Now let us bring down 25, making the new<a>dividend</a>625. Add the old<a>divisor</a>with the same number: 3 + 3, we get 6, which will be our new divisor.</p>
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<p><strong>Step 4:</strong>The new divisor will be the sum of the dividend and quotient. Now we get 6n as the new divisor, we need to find the value of n.</p>
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<p><strong>Step 4:</strong>The new divisor will be the sum of the dividend and quotient. Now we get 6n as the new divisor, we need to find the value of n.</p>
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<p><strong>Step 5:</strong>The next step is finding 6n × n ≤ 625. Let us consider n as 10, now 60 x 10 = 600.</p>
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<p><strong>Step 5:</strong>The next step is finding 6n × n ≤ 625. Let us consider n as 10, now 60 x 10 = 600.</p>
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<p><strong>Step 6:</strong>Subtract 600 from 625, the difference is 25, and the quotient is 30.</p>
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<p><strong>Step 6:</strong>Subtract 600 from 625, the difference is 25, and the quotient is 30.</p>
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<p><strong>Step 7:</strong>Since the dividend is less than the divisor, we need to add a decimal point. Adding the decimal point allows us to add two zeroes to the dividend. Now the new dividend is 2500.</p>
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<p><strong>Step 7:</strong>Since the dividend is less than the divisor, we need to add a decimal point. Adding the decimal point allows us to add two zeroes to the dividend. Now the new dividend is 2500.</p>
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<p><strong>Step 8:</strong>Now we need to find the new divisor, which is 390 because 390 x 6 = 2340.</p>
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<p><strong>Step 8:</strong>Now we need to find the new divisor, which is 390 because 390 x 6 = 2340.</p>
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<p><strong>Step 9:</strong>Subtracting 2340 from 2500, we get the result 160.</p>
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<p><strong>Step 9:</strong>Subtracting 2340 from 2500, we get the result 160.</p>
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<p><strong>Step 10:</strong>Now the quotient is 39.0.</p>
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<p><strong>Step 10:</strong>Now the quotient is 39.0.</p>
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<p><strong>Step 11:</strong>Continue doing these steps until we get two numbers after the decimal point. Continue until the remainder is zero or a desired precision is achieved.</p>
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<p><strong>Step 11:</strong>Continue doing these steps until we get two numbers after the decimal point. Continue until the remainder is zero or a desired precision is achieved.</p>
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<p>So the square root of √1525 is approximately 39.05.</p>
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<p>So the square root of √1525 is approximately 39.05.</p>
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