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2 <p>Last updated on<strong>August 5, 2025</strong></p>

3 <p>If a number is multiplied by itself, the result is a square. The inverse operation is finding the square root. The square root has applications in various fields such as engineering, physics, and finance. Here, we will discuss the square root of 167.</p>

4 <h2>What is the Square Root of 167?</h2>

5 <p>The<a>square</a>root is the inverse operation of squaring a<a>number</a>. 167 is not a<a>perfect square</a>. The square root of 167 can be expressed in both radical and exponential forms. In the radical form, it is expressed as √167, whereas in the<a>exponential form</a>, it is expressed as (167(1/2) .The approximate value of √167 is 12.9228, which is an<a>irrational number</a>because it cannot be expressed as a<a>fraction</a>of two<a>integers</a>.</p>

6 <h2>Finding the Square Root of 167</h2>

7 <p>For perfect square numbers, the<a>prime factorization</a>method is effective. However, for non-perfect squares like 167, the<a>long division</a>method and approximation method are more suitable. Let's explore these methods:</p>

8 <ul><li>Prime factorization method </li>

9 <li>Long division method </li>

10 <li>Approximation method</li>

11 </ul><h3>Square Root of 167 by Prime Factorization Method</h3>

12 <p>Prime factorization involves expressing a number as a<a>product</a>of<a>prime numbers</a>.</p>

13 <p>For 167, the prime factorization is straightforward since 167 is a prime number itself. Thus, it cannot be factored further.</p>

14 <p>Since 167 is not a perfect square, we cannot pair its prime<a>factors</a>to simplify the<a>square root</a>. Therefore, calculating √167 using prime factorization is not feasible.</p>

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17 <h3>Square Root of 167 by Long Division Method</h3>

16 <h3>Square Root of 167 by Long Division Method</h3>

18 <p>The long<a>division</a>method is used for finding the square roots of non-perfect square numbers. Here’s how it works for 167:</p>

17 <p>The long<a>division</a>method is used for finding the square roots of non-perfect square numbers. Here’s how it works for 167:</p>

19 <p><strong>Step 1:</strong>Group the number from right to left. In the case of 167, we group it as (1)(67).</p>

18 <p><strong>Step 1:</strong>Group the number from right to left. In the case of 167, we group it as (1)(67).</p>

20 <p><strong>Step 2:</strong>Find a number n whose square is<a>less than</a>or equal to 1. Here, n is 1 since 1^2 = 1. The<a>quotient</a>becomes 1, and the<a>remainder</a>is 0.</p>

19 <p><strong>Step 2:</strong>Find a number n whose square is<a>less than</a>or equal to 1. Here, n is 1 since 1^2 = 1. The<a>quotient</a>becomes 1, and the<a>remainder</a>is 0.</p>

21 <p><strong>Step 3:</strong>Bring down the next group, 67, making the new<a>dividend</a>67. Add the previous<a>divisor</a>(1) to itself to get 2, which is part of the new divisor.</p>

20 <p><strong>Step 3:</strong>Bring down the next group, 67, making the new<a>dividend</a>67. Add the previous<a>divisor</a>(1) to itself to get 2, which is part of the new divisor.</p>

22 <p><strong>Step 4:</strong>Consider 2n as the new divisor. We need to find n such that 2n × n ≤ 67. Trying n as 3 gives 23 × 3 = 69, which is too large. Trying n as 2 gives 22 × 2 = 44, which fits.</p>

21 <p><strong>Step 4:</strong>Consider 2n as the new divisor. We need to find n such that 2n × n ≤ 67. Trying n as 3 gives 23 × 3 = 69, which is too large. Trying n as 2 gives 22 × 2 = 44, which fits.</p>

23 <p><strong>Step 5:</strong>Subtract 44 from 67 to get a remainder of 23.</p>

22 <p><strong>Step 5:</strong>Subtract 44 from 67 to get a remainder of 23.</p>

24 <p><strong>Step 6:</strong>Since the new dividend is smaller than the divisor, add a<a>decimal</a>point and bring down two zeros to make it 2300.</p>

23 <p><strong>Step 6:</strong>Since the new dividend is smaller than the divisor, add a<a>decimal</a>point and bring down two zeros to make it 2300.</p>

25 <p><strong>Step 7:</strong>Find the new divisor, which becomes 249 (since the previous quotient was 12). Find n such that 249n × n ≤ 2300. Trying n as 9 gives 2499 × 9 = 2241.</p>

24 <p><strong>Step 7:</strong>Find the new divisor, which becomes 249 (since the previous quotient was 12). Find n such that 249n × n ≤ 2300. Trying n as 9 gives 2499 × 9 = 2241.</p>

26 <p><strong>Step 8:</strong>Subtract 2241 from 2300 to get a remainder of 59.</p>

25 <p><strong>Step 8:</strong>Subtract 2241 from 2300 to get a remainder of 59.</p>

27 <p><strong>Step 9:</strong>Continue this process to get more decimal places as needed.</p>

26 <p><strong>Step 9:</strong>Continue this process to get more decimal places as needed.</p>

28 <p>Thus, √167 ≈ 12.9228.</p>

27 <p>Thus, √167 ≈ 12.9228.</p>

29 <h3>Square Root of 167 by Approximation Method</h3>

28 <h3>Square Root of 167 by Approximation Method</h3>

30 <p>Approximation is a simpler method to estimate square roots. Follow these steps for √167:</p>

29 <p>Approximation is a simpler method to estimate square roots. Follow these steps for √167:</p>

31 <p><strong>Step 1:</strong>Identify the closest perfect squares. 144 and 169 are the nearest perfect squares to 167. √167 lies between √144 (12) and √169 (13).</p>

30 <p><strong>Step 1:</strong>Identify the closest perfect squares. 144 and 169 are the nearest perfect squares to 167. √167 lies between √144 (12) and √169 (13).</p>

32 <p><strong>Step 2:</strong>Use the<a>formula</a>to approximate: (Given number - smaller perfect square) / (Greater perfect square - smaller perfect square). For 167, (167 - 144) / (169 - 144) = 23 / 25 = 0.92. Step 3: Add the approximation to the smaller square root value: 12 + 0.92 = 12.92.</p>

31 <p><strong>Step 2:</strong>Use the<a>formula</a>to approximate: (Given number - smaller perfect square) / (Greater perfect square - smaller perfect square). For 167, (167 - 144) / (169 - 144) = 23 / 25 = 0.92. Step 3: Add the approximation to the smaller square root value: 12 + 0.92 = 12.92.</p>

33 <p>Therefore, √167 is approximately 12.92.</p>

32 <p>Therefore, √167 is approximately 12.92.</p>

34 <h2>Common Mistakes and How to Avoid Them in the Square Root of 167</h2>

33 <h2>Common Mistakes and How to Avoid Them in the Square Root of 167</h2>

35 <p>Errors can occur while calculating square roots, such as ignoring the negative root or misapplying methods. Let's examine some common mistakes:</p>

34 <p>Errors can occur while calculating square roots, such as ignoring the negative root or misapplying methods. Let's examine some common mistakes:</p>

35 + <h2>Download Worksheets</h2>

36 <h3>Problem 1</h3>

37 <p>Can you help Max find the area of a square box if its side length is given as √167?</p>

38 <p>Okay, lets begin</p>

39 <p>The area of the square is approximately 167 square units.</p>

40 <h3>Explanation</h3>

41 <p>The area of the square = side^2.</p>

42 <p>The side length is given as √167.</p>

43 <p>Area of the square = (√167)^2</p>

44 <p>= 167.</p>

45 <p>Therefore, the area of the square box is approximately 167 square units.</p>

46 <p>Well explained 👍</p>

47 <h3>Problem 2</h3>

48 <p>A square-shaped garden measuring 167 square feet is being designed; if each side is √167, what will be the square feet of half of the garden?</p>

49 <p>Okay, lets begin</p>

50 <p>83.5 square feet</p>

51 <h3>Explanation</h3>

52 <p>Since the garden is square-shaped, dividing the total area by 2 gives the area of half the garden.</p>

53 <p>167 / 2 = 83.5</p>

54 <p>So, half of the garden measures 83.5 square feet.</p>

55 <p>Well explained 👍</p>

56 <h3>Problem 3</h3>

57 <p>Calculate √167 × 4.</p>

58 <p>Okay, lets begin</p>

59 <p>Approximately 51.69</p>

60 <h3>Explanation</h3>

61 <p>First, find the square root of 167, which is approximately 12.9228. Multiply this by 4. 12.9228 × 4 ≈ 51.69</p>

62 <p>Well explained 👍</p>

63 <h3>Problem 4</h3>

64 <p>What is the square root of (149 + 18)?</p>

65 <p>Okay, lets begin</p>

66 <p>The square root is 13.</p>

67 <h3>Explanation</h3>

68 <p>Calculate the sum inside the parentheses: 149 + 18 = 167.</p>

69 <p>The square root of 167 is approximately 12.9228, which rounds to 13.</p>

70 <p>Therefore, the square root of (149 + 18) is approximately 13.</p>

71 <p>Well explained 👍</p>

72 <h3>Problem 5</h3>

73 <p>Find the perimeter of a rectangle if its length ‘l’ is √167 units and the width ‘w’ is 40 units.</p>

74 <p>Okay, lets begin</p>

75 <p>The perimeter of the rectangle is approximately 105.85 units.</p>

76 <h3>Explanation</h3>

77 <p>Perimeter of the rectangle = 2 × (length + width)</p>

78 <p>Perimeter = 2 × (√167 + 40)</p>

79 <p>= 2 × (12.9228 + 40)</p>

80 <p>≈ 105.85 units.</p>

81 <p>Well explained 👍</p>

82 <h2>FAQ on Square Root of 167</h2>

83 <h3>1.What is √167 in its simplest form?</h3>

84 <p>Since 167 is a prime number, its simplest radical form is √167.</p>

85 <h3>2.Mention the factors of 167.</h3>

86 <p>The factors of 167 are 1 and 167, as it is a prime number.</p>

87 <h3>3.Calculate the square of 167.</h3>

88 <p>The square of 167 is 167 × 167 = 27,889.</p>

89 <h3>4.Is 167 a prime number?</h3>

90 <p>Yes, 167 is a prime number because it has only two factors: 1 and 167.</p>

91 <h3>5.167 is divisible by?</h3>

92 <p>167 is only divisible by 1 and 167 as it is a prime number.</p>

93 <h2>Important Glossaries for the Square Root of 167</h2>

94 <ul><li><strong>Square root:</strong>The number that, when multiplied by itself, gives the original number. Example: √16 = 4 because 4 × 4 = 16. </li>

95 <li><strong>Irrational number:</strong>A number that cannot be expressed as a simple fraction, with a non-repeating and non-terminating decimal. Example: √2. </li>

96 <li><strong>Prime number:</strong>A natural number greater than 1 that has no positive divisors other than 1 and itself. Example: 167. </li>

97 <li><strong>Approximation:</strong>The process of finding a value that is close to but not exactly equal to a specific number. </li>

98 <li><strong>Perfect square:</strong>A number that is the square of an integer. Example: 144, as 12 × 12 = 144.</li>

99 </ul><p>What Is Algebra? 🧮 | Simple Explanation with 🎯 Cool Examples for Kids | ✨BrightCHAMPS Math</p>

100 <p>▶</p>

101 <h2>Jaskaran Singh Saluja</h2>

102 <h3>About the Author</h3>

103 <p>Jaskaran Singh Saluja is a math wizard with nearly three years of experience as a math teacher. His expertise is in algebra, so he can make algebra classes interesting by turning tricky equations into simple puzzles.</p>

104 <h3>Fun Fact</h3>

105 <p>: He loves to play the quiz with kids through algebra to make kids love it.</p>