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Original
2026-01-01
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2026-02-28
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<p>The<a>long division</a>method is particularly used for non-perfect square numbers. In this method, we should check the closest perfect square number for the given number. Let us now learn how to find the<a>square root</a>using the long division method, step by step.</p>
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<p>The<a>long division</a>method is particularly used for non-perfect square numbers. In this method, we should check the closest perfect square number for the given number. Let us now learn how to find the<a>square root</a>using the long division method, step by step.</p>
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<p><strong>Step 1:</strong>To begin with, we need to group the numbers from right to left. In the case of 1290, we need to group it as 90 and 12.</p>
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<p><strong>Step 1:</strong>To begin with, we need to group the numbers from right to left. In the case of 1290, we need to group it as 90 and 12.</p>
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<p><strong>Step 2:</strong>Now we need to find n whose square is ≤ 12. We can say n as ‘3’ because 3 x 3 = 9 is lesser than or equal to 12. Now the<a>quotient</a>is 3, after subtracting 9 from 12, the<a>remainder</a>is 3.</p>
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<p><strong>Step 2:</strong>Now we need to find n whose square is ≤ 12. We can say n as ‘3’ because 3 x 3 = 9 is lesser than or equal to 12. Now the<a>quotient</a>is 3, after subtracting 9 from 12, the<a>remainder</a>is 3.</p>
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<p><strong>Step 3:</strong>Now let us bring down 90, which is the new<a>dividend</a>. Add the old<a>divisor</a>with the same number 3 + 3, we get 6, which will be our new divisor.</p>
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<p><strong>Step 3:</strong>Now let us bring down 90, which is the new<a>dividend</a>. Add the old<a>divisor</a>with the same number 3 + 3, we get 6, which will be our new divisor.</p>
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<p><strong>Step 4:</strong>The new divisor will be the<a>sum</a>of the dividend and quotient. Now we get 6n as the new divisor, and we need to find the value of n.</p>
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<p><strong>Step 4:</strong>The new divisor will be the<a>sum</a>of the dividend and quotient. Now we get 6n as the new divisor, and we need to find the value of n.</p>
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<p><strong>Step 5:</strong>The next step is finding 6n × n ≤ 390. Let us consider n as 6, now 66 x 6 = 396, which is too high; try n as 5, then 65 x 5 = 325.</p>
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<p><strong>Step 5:</strong>The next step is finding 6n × n ≤ 390. Let us consider n as 6, now 66 x 6 = 396, which is too high; try n as 5, then 65 x 5 = 325.</p>
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<p><strong>Step 6:</strong>Subtract 325 from 390; the difference is 65, and the quotient is 35.</p>
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<p><strong>Step 6:</strong>Subtract 325 from 390; the difference is 65, and the quotient is 35.</p>
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<p><strong>Step 7:</strong>Since the dividend is less than the divisor, we need to add a decimal point. Adding the decimal point allows us to add two zeroes to the dividend. Now the new dividend is 6500.</p>
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<p><strong>Step 7:</strong>Since the dividend is less than the divisor, we need to add a decimal point. Adding the decimal point allows us to add two zeroes to the dividend. Now the new dividend is 6500.</p>
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<p><strong>Step 8:</strong>Now we need to find the new divisor, which is 709 because 709 x 9 = 6381.</p>
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<p><strong>Step 8:</strong>Now we need to find the new divisor, which is 709 because 709 x 9 = 6381.</p>
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<p><strong>Step 9:</strong>Subtracting 6381 from 6500, we get the result 119.</p>
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<p><strong>Step 9:</strong>Subtracting 6381 from 6500, we get the result 119.</p>
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<p><strong>Step 10:</strong>Now the quotient is 35.8.</p>
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<p><strong>Step 10:</strong>Now the quotient is 35.8.</p>
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<p><strong>Step 11:</strong>Continue doing these steps until we get two numbers after the decimal point. Suppose if there are no decimal values, continue till the remainder is zero.</p>
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<p><strong>Step 11:</strong>Continue doing these steps until we get two numbers after the decimal point. Suppose if there are no decimal values, continue till the remainder is zero.</p>
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<p>So the square root of √1290 is approximately 35.89.</p>
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<p>So the square root of √1290 is approximately 35.89.</p>
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