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Original
2026-01-01
Modified
2026-02-28
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<p>201 Learners</p>
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<p>Last updated on<strong>August 5, 2025</strong></p>
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<p>Last updated on<strong>August 5, 2025</strong></p>
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<p>If a number is multiplied by itself, the result is a square. The inverse of the square is a square root. The square root is used in fields such as vehicle design, finance, etc. Here, we will discuss the square root of 2640.</p>
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<p>If a number is multiplied by itself, the result is a square. The inverse of the square is a square root. The square root is used in fields such as vehicle design, finance, etc. Here, we will discuss the square root of 2640.</p>
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<h2>What is the Square Root of 2640?</h2>
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<h2>What is the Square Root of 2640?</h2>
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<p>The<a>square</a>root is the inverse<a>of</a>squaring a<a>number</a>. 2640 is not a<a>perfect square</a>. The square root of 2640 is expressed in both radical and exponential forms. In the radical form, it is expressed as √2640, whereas (2640)^(1/2) is the<a>exponential form</a>. √2640 ≈ 51.384, which is an<a>irrational number</a>because it cannot be expressed as a<a>fraction</a>p/q, where p and q are integers and q ≠ 0.</p>
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<p>The<a>square</a>root is the inverse<a>of</a>squaring a<a>number</a>. 2640 is not a<a>perfect square</a>. The square root of 2640 is expressed in both radical and exponential forms. In the radical form, it is expressed as √2640, whereas (2640)^(1/2) is the<a>exponential form</a>. √2640 ≈ 51.384, which is an<a>irrational number</a>because it cannot be expressed as a<a>fraction</a>p/q, where p and q are integers and q ≠ 0.</p>
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<h2>Finding the Square Root of 2640</h2>
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<h2>Finding the Square Root of 2640</h2>
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<p>The<a>prime factorization</a>method is used for perfect square numbers. However, for non-perfect square numbers, the long-<a>division</a>method and approximation method are used. Let us now learn the following methods:</p>
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<p>The<a>prime factorization</a>method is used for perfect square numbers. However, for non-perfect square numbers, the long-<a>division</a>method and approximation method are used. Let us now learn the following methods:</p>
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<ul><li>Prime factorization method</li>
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<ul><li>Prime factorization method</li>
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<li>Long division method</li>
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<li>Long division method</li>
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<li>Approximation method</li>
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<li>Approximation method</li>
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</ul><h2>Square Root of 2640 by Prime Factorization Method</h2>
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</ul><h2>Square Root of 2640 by Prime Factorization Method</h2>
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<p>The<a>product</a>of prime<a>factors</a>is the prime factorization of a number. Now let us look at how 2640 is broken down into its prime factors:</p>
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<p>The<a>product</a>of prime<a>factors</a>is the prime factorization of a number. Now let us look at how 2640 is broken down into its prime factors:</p>
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<p><strong>Step 1:</strong>Finding the prime factors of 2640 Breaking it down, we get 2 x 2 x 2 x 3 x 5 x 11 = 2^3 x 3 x 5 x 11</p>
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<p><strong>Step 1:</strong>Finding the prime factors of 2640 Breaking it down, we get 2 x 2 x 2 x 3 x 5 x 11 = 2^3 x 3 x 5 x 11</p>
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<p><strong>Step 2:</strong>Now we found the prime factors of 2640. The next step is to make pairs of those prime factors. Since 2640 is not a perfect square, the digits cannot be completely paired.</p>
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<p><strong>Step 2:</strong>Now we found the prime factors of 2640. The next step is to make pairs of those prime factors. Since 2640 is not a perfect square, the digits cannot be completely paired.</p>
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<p>Therefore, calculating √2640 using prime factorization directly is not feasible.</p>
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<p>Therefore, calculating √2640 using prime factorization directly is not feasible.</p>
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<h2>Square Root of 2640 by Long Division Method</h2>
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<h2>Square Root of 2640 by Long Division Method</h2>
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<p>The<a>long division</a>method is particularly used for non-perfect square numbers. In this method, we find the closest perfect square number for the given number. Let us now learn how to find the<a>square root</a>using the long division method, step by step:</p>
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<p>The<a>long division</a>method is particularly used for non-perfect square numbers. In this method, we find the closest perfect square number for the given number. Let us now learn how to find the<a>square root</a>using the long division method, step by step:</p>
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<p><strong>Step 1:</strong>To begin with, group the numbers from right to left. For 2640, group it as 40 and 26.</p>
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<p><strong>Step 1:</strong>To begin with, group the numbers from right to left. For 2640, group it as 40 and 26.</p>
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<p><strong>Step 2:</strong>Find n whose square is<a>less than</a>or equal to 26. We can say n is 5 because 5^2 = 25. Now the<a>quotient</a>is 5, and after subtracting 25 from 26, the<a>remainder</a>is 1.</p>
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<p><strong>Step 2:</strong>Find n whose square is<a>less than</a>or equal to 26. We can say n is 5 because 5^2 = 25. Now the<a>quotient</a>is 5, and after subtracting 25 from 26, the<a>remainder</a>is 1.</p>
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<p><strong>Step 3:</strong>Bring down 40, making the new<a>dividend</a>140. Add the old<a>divisor</a>with the same number: 5 + 5 = 10, which will be our new divisor.</p>
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<p><strong>Step 3:</strong>Bring down 40, making the new<a>dividend</a>140. Add the old<a>divisor</a>with the same number: 5 + 5 = 10, which will be our new divisor.</p>
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<p><strong>Step 4:</strong>The new divisor is 10n. We need to find the value of n.</p>
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<p><strong>Step 4:</strong>The new divisor is 10n. We need to find the value of n.</p>
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<p><strong>Step 5:</strong>Find 10n × n ≤ 140. Let n be 1, then 10 × 1 × 1 = 10.</p>
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<p><strong>Step 5:</strong>Find 10n × n ≤ 140. Let n be 1, then 10 × 1 × 1 = 10.</p>
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<p><strong>Step 6:</strong>Subtract 10 from 140, leaving a remainder of 130, with the quotient now 51.</p>
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<p><strong>Step 6:</strong>Subtract 10 from 140, leaving a remainder of 130, with the quotient now 51.</p>
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<p><strong>Step 7:</strong>Since the dividend is less than the divisor, we need to add a decimal point. Adding the decimal point allows us to add two zeroes to the dividend. The new dividend is 13000.</p>
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<p><strong>Step 7:</strong>Since the dividend is less than the divisor, we need to add a decimal point. Adding the decimal point allows us to add two zeroes to the dividend. The new dividend is 13000.</p>
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<p><strong>Step 8:</strong>Find the new divisor, which is 101. Then 101 × 1 = 101.</p>
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<p><strong>Step 8:</strong>Find the new divisor, which is 101. Then 101 × 1 = 101.</p>
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<p><strong>Step 9:</strong>Subtract 101 from 13000 to get the result 12899.</p>
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<p><strong>Step 9:</strong>Subtract 101 from 13000 to get the result 12899.</p>
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<p><strong>Step 10:</strong>The quotient is now approximately 51.3.</p>
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<p><strong>Step 10:</strong>The quotient is now approximately 51.3.</p>
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<p><strong>Step 11:</strong>Continue these steps until we have two decimal places. If there are no decimal values, continue until the remainder is zero.</p>
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<p><strong>Step 11:</strong>Continue these steps until we have two decimal places. If there are no decimal values, continue until the remainder is zero.</p>
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<p>So the square root of √2640 is approximately 51.38.</p>
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<p>So the square root of √2640 is approximately 51.38.</p>
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<h2>Square Root of 2640 by Approximation Method</h2>
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<h2>Square Root of 2640 by Approximation Method</h2>
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<p>The approximation method is an easy method to find the square root of a given number. Let's learn how to find the square root of 2640 using the approximation method.</p>
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<p>The approximation method is an easy method to find the square root of a given number. Let's learn how to find the square root of 2640 using the approximation method.</p>
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<p><strong>Step 1:</strong>Identify the closest perfect squares to √2640. The smallest perfect square less than 2640 is 2601 (51^2), and the largest perfect square<a>greater than</a>2640 is 2704 (52^2). √2640 falls between 51 and 52.</p>
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<p><strong>Step 1:</strong>Identify the closest perfect squares to √2640. The smallest perfect square less than 2640 is 2601 (51^2), and the largest perfect square<a>greater than</a>2640 is 2704 (52^2). √2640 falls between 51 and 52.</p>
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<p><strong>Step 2:</strong>Apply the<a>formula</a>: (Given number - smaller perfect square) / (larger perfect square - smaller perfect square) (2640 - 2601) / (2704 - 2601) = 39 / 103 ≈ 0.379 Using the formula, we identify the<a>decimal</a>point of our square root. Adding the initial<a>integer</a>value, 51 + 0.38 = 51.38.</p>
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<p><strong>Step 2:</strong>Apply the<a>formula</a>: (Given number - smaller perfect square) / (larger perfect square - smaller perfect square) (2640 - 2601) / (2704 - 2601) = 39 / 103 ≈ 0.379 Using the formula, we identify the<a>decimal</a>point of our square root. Adding the initial<a>integer</a>value, 51 + 0.38 = 51.38.</p>
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<p>So the square root of 2640 is approximately 51.38.</p>
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<p>So the square root of 2640 is approximately 51.38.</p>
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<h2>Common Mistakes and How to Avoid Them in the Square Root of 2640</h2>
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<h2>Common Mistakes and How to Avoid Them in the Square Root of 2640</h2>
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<p>Students often make mistakes while finding the square root, such as forgetting about the negative square root or skipping the long division method. Let's look at a few of these mistakes in detail.</p>
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<p>Students often make mistakes while finding the square root, such as forgetting about the negative square root or skipping the long division method. Let's look at a few of these mistakes in detail.</p>
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<h2>Download Worksheets</h2>
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<h3>Problem 1</h3>
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<h3>Problem 1</h3>
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<p>Calculate √2640 x 3.</p>
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<p>Calculate √2640 x 3.</p>
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<p>Okay, lets begin</p>
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<p>Okay, lets begin</p>
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<p>154.152</p>
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<p>154.152</p>
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<h3>Explanation</h3>
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<h3>Explanation</h3>
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<p>First, find the square root of 2640, which is approximately 51.384.</p>
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<p>First, find the square root of 2640, which is approximately 51.384.</p>
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<p>Then, multiply 51.384 by 3. 51.384 x 3 ≈ 154.152</p>
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<p>Then, multiply 51.384 by 3. 51.384 x 3 ≈ 154.152</p>
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<p>Well explained 👍</p>
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<p>Well explained 👍</p>
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<h3>Problem 2</h3>
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<h3>Problem 2</h3>
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<p>The area of a square is 2640 square feet. What is the length of one side of the square?</p>
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<p>The area of a square is 2640 square feet. What is the length of one side of the square?</p>
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<p>Okay, lets begin</p>
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<p>Okay, lets begin</p>
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<p>Approximately 51.38 feet</p>
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<p>Approximately 51.38 feet</p>
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<h3>Explanation</h3>
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<h3>Explanation</h3>
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<p>If the area of the square is 2640 square feet, the side length is the square root of 2640. √2640 ≈ 51.38 feet</p>
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<p>If the area of the square is 2640 square feet, the side length is the square root of 2640. √2640 ≈ 51.38 feet</p>
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<p>Well explained 👍</p>
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<p>Well explained 👍</p>
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<h3>Problem 3</h3>
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<h3>Problem 3</h3>
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<p>What will be the square root of (2640 + 10)?</p>
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<p>What will be the square root of (2640 + 10)?</p>
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<p>Okay, lets begin</p>
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<p>Okay, lets begin</p>
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<p>Approximately 51.58</p>
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<p>Approximately 51.58</p>
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<h3>Explanation</h3>
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<h3>Explanation</h3>
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<p>To find the square root, first calculate the sum of (2640 + 10) = 2650. Then, √2650 ≈ 51.58.</p>
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<p>To find the square root, first calculate the sum of (2640 + 10) = 2650. Then, √2650 ≈ 51.58.</p>
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<p>Well explained 👍</p>
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<p>Well explained 👍</p>
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<h3>Problem 4</h3>
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<h3>Problem 4</h3>
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<p>Find the perimeter of a square with a side length of √2640 units.</p>
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<p>Find the perimeter of a square with a side length of √2640 units.</p>
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<p>Okay, lets begin</p>
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<p>Okay, lets begin</p>
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<p>205.536 units</p>
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<p>205.536 units</p>
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<h3>Explanation</h3>
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<h3>Explanation</h3>
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<p>Perimeter of a square = 4 × side length.</p>
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<p>Perimeter of a square = 4 × side length.</p>
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<p>If the side length is √2640, then the perimeter is 4 × 51.384 ≈ 205.536 units.</p>
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<p>If the side length is √2640, then the perimeter is 4 × 51.384 ≈ 205.536 units.</p>
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<p>Well explained 👍</p>
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<p>Well explained 👍</p>
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<h3>Problem 5</h3>
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<h3>Problem 5</h3>
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<p>A rectangular garden measures 2640 square feet. If its length is 60 feet, what is the width?</p>
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<p>A rectangular garden measures 2640 square feet. If its length is 60 feet, what is the width?</p>
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<p>Okay, lets begin</p>
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<p>Okay, lets begin</p>
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<p>44 feet</p>
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<p>44 feet</p>
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<h3>Explanation</h3>
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<h3>Explanation</h3>
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<p>To find the width, divide the area by the length: Width = Area / Length = 2640 / 60 = 44 feet</p>
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<p>To find the width, divide the area by the length: Width = Area / Length = 2640 / 60 = 44 feet</p>
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<p>Well explained 👍</p>
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<p>Well explained 👍</p>
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<h2>FAQ on Square Root of 2640</h2>
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<h2>FAQ on Square Root of 2640</h2>
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<h3>1.What is √2640 in its simplest form?</h3>
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<h3>1.What is √2640 in its simplest form?</h3>
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<p>The prime factorization of 2640 is 2^3 x 3 x 5 x 11, so the simplest form of √2640 = √(2^3 x 3 x 5 x 11)</p>
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<p>The prime factorization of 2640 is 2^3 x 3 x 5 x 11, so the simplest form of √2640 = √(2^3 x 3 x 5 x 11)</p>
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<h3>2.Mention the factors of 2640.</h3>
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<h3>2.Mention the factors of 2640.</h3>
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<p>Factors of 2640 include 1, 2, 3, 4, 5, 6, 8, 10, 11, 12, 15, 16, 20, 22, 24, 30, 33, 40, 44, 48, 55, 60, 66, 80, 88, 110, 120, 132, 165, 176, 220, 240, 264, 330, 440, 528, 660, 880, 1320, and 2640.</p>
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<p>Factors of 2640 include 1, 2, 3, 4, 5, 6, 8, 10, 11, 12, 15, 16, 20, 22, 24, 30, 33, 40, 44, 48, 55, 60, 66, 80, 88, 110, 120, 132, 165, 176, 220, 240, 264, 330, 440, 528, 660, 880, 1320, and 2640.</p>
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<h3>3.Calculate the square of 2640.</h3>
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<h3>3.Calculate the square of 2640.</h3>
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<p>The square of 2640 is found by multiplying the number by itself: 2640 x 2640 = 6,969,600.</p>
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<p>The square of 2640 is found by multiplying the number by itself: 2640 x 2640 = 6,969,600.</p>
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<h3>4.Is 2640 a prime number?</h3>
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<h3>4.Is 2640 a prime number?</h3>
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<p>2640 is not a<a>prime number</a>, as it has more than two factors.</p>
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<p>2640 is not a<a>prime number</a>, as it has more than two factors.</p>
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<h3>5.2640 is divisible by?</h3>
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<h3>5.2640 is divisible by?</h3>
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<p>2640 has many factors; it is divisible by 1, 2, 3, 4, 5, 6, 8, 10, 11, 12, 15, 16, 20, 22, 24, 30, 33, 40, 44, 48, 55, 60, 66, 80, 88, 110, 120, 132, 165, 176, 220, 240, 264, 330, 440, 528, 660, 880, 1320, and 2640.</p>
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<p>2640 has many factors; it is divisible by 1, 2, 3, 4, 5, 6, 8, 10, 11, 12, 15, 16, 20, 22, 24, 30, 33, 40, 44, 48, 55, 60, 66, 80, 88, 110, 120, 132, 165, 176, 220, 240, 264, 330, 440, 528, 660, 880, 1320, and 2640.</p>
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<h2>Important Glossaries for the Square Root of 2640</h2>
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<h2>Important Glossaries for the Square Root of 2640</h2>
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<ul><li><strong>Square root:</strong>A square root is the inverse operation of squaring a number. Example: 4^2 = 16, and the inverse of the square is the square root, so √16 = 4. </li>
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<ul><li><strong>Square root:</strong>A square root is the inverse operation of squaring a number. Example: 4^2 = 16, and the inverse of the square is the square root, so √16 = 4. </li>
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<li><strong>Irrational number:</strong>An irrational number cannot be expressed as a fraction p/q, where q is not equal to zero and p and q are integers. </li>
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<li><strong>Irrational number:</strong>An irrational number cannot be expressed as a fraction p/q, where q is not equal to zero and p and q are integers. </li>
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<li><strong>Perfect square:</strong>A perfect square is a number that is the square of an integer. For example, 16 is a perfect square because it is 4^2. </li>
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<li><strong>Perfect square:</strong>A perfect square is a number that is the square of an integer. For example, 16 is a perfect square because it is 4^2. </li>
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<li><strong>Long division method:</strong>A method used to find the square root of a non-perfect square number by dividing and averaging. </li>
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<li><strong>Long division method:</strong>A method used to find the square root of a non-perfect square number by dividing and averaging. </li>
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<li><strong>Approximation method:</strong>A technique to estimate the square root of a number by identifying nearby perfect squares and calculating a closer value.</li>
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<li><strong>Approximation method:</strong>A technique to estimate the square root of a number by identifying nearby perfect squares and calculating a closer value.</li>
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</ul><p>What Is Algebra? 🧮 | Simple Explanation with 🎯 Cool Examples for Kids | ✨BrightCHAMPS Math</p>
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</ul><p>What Is Algebra? 🧮 | Simple Explanation with 🎯 Cool Examples for Kids | ✨BrightCHAMPS Math</p>
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<p>▶</p>
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<p>▶</p>
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<h2>Jaskaran Singh Saluja</h2>
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<h2>Jaskaran Singh Saluja</h2>
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<h3>About the Author</h3>
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<h3>About the Author</h3>
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<p>Jaskaran Singh Saluja is a math wizard with nearly three years of experience as a math teacher. His expertise is in algebra, so he can make algebra classes interesting by turning tricky equations into simple puzzles.</p>
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<p>Jaskaran Singh Saluja is a math wizard with nearly three years of experience as a math teacher. His expertise is in algebra, so he can make algebra classes interesting by turning tricky equations into simple puzzles.</p>
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<h3>Fun Fact</h3>
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<h3>Fun Fact</h3>
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<p>: He loves to play the quiz with kids through algebra to make kids love it.</p>
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<p>: He loves to play the quiz with kids through algebra to make kids love it.</p>