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1 - <p>224 Learners</p>
1 + <p>268 Learners</p>
2 <p>Last updated on<strong>August 5, 2025</strong></p>
2 <p>Last updated on<strong>August 5, 2025</strong></p>
3 <p>If a number is multiplied by the same number, the result is a square. The inverse of the square is a square root. The square root is used in the field of vehicle design, finance, etc. Here, we will discuss the square root of 650.</p>
3 <p>If a number is multiplied by the same number, the result is a square. The inverse of the square is a square root. The square root is used in the field of vehicle design, finance, etc. Here, we will discuss the square root of 650.</p>
4 <h2>What is the Square Root of 650?</h2>
4 <h2>What is the Square Root of 650?</h2>
5 <p>The<a>square</a>root is the inverse of the square of a<a>number</a>. 650 is not a<a>perfect square</a>. The square root of 650 is expressed in both radical and<a>exponential form</a>. In the radical form, it is expressed as √650, whereas (650)^(1/2) in the exponential form. √650 ≈ 25.4951, which is an<a>irrational number</a>because it cannot be expressed in the form of p/q, where p and q are<a>integers</a>and q ≠ 0.</p>
5 <p>The<a>square</a>root is the inverse of the square of a<a>number</a>. 650 is not a<a>perfect square</a>. The square root of 650 is expressed in both radical and<a>exponential form</a>. In the radical form, it is expressed as √650, whereas (650)^(1/2) in the exponential form. √650 ≈ 25.4951, which is an<a>irrational number</a>because it cannot be expressed in the form of p/q, where p and q are<a>integers</a>and q ≠ 0.</p>
6 <h2>Finding the Square Root of 650</h2>
6 <h2>Finding the Square Root of 650</h2>
7 <p>The<a>prime factorization</a>method is used for perfect square numbers. However, the prime factorization method is not used for non-perfect square numbers where<a>long division</a>method and approximation method are used. Let us now learn the following methods:</p>
7 <p>The<a>prime factorization</a>method is used for perfect square numbers. However, the prime factorization method is not used for non-perfect square numbers where<a>long division</a>method and approximation method are used. Let us now learn the following methods:</p>
8 <ul><li>Prime factorization method</li>
8 <ul><li>Prime factorization method</li>
9 <li>Long division method</li>
9 <li>Long division method</li>
10 <li>Approximation method</li>
10 <li>Approximation method</li>
11 </ul><h2>Square Root of 650 by Prime Factorization Method</h2>
11 </ul><h2>Square Root of 650 by Prime Factorization Method</h2>
12 <p>The<a>product</a>of prime<a>factors</a>is the prime factorization of a number. Now let us look at how 650 is broken down into its prime factors.</p>
12 <p>The<a>product</a>of prime<a>factors</a>is the prime factorization of a number. Now let us look at how 650 is broken down into its prime factors.</p>
13 <p><strong>Step 1:</strong>Finding the prime factors of 650 Breaking it down, we get 2 x 5 x 5 x 13: 2^1 x 5^2 x 13^1</p>
13 <p><strong>Step 1:</strong>Finding the prime factors of 650 Breaking it down, we get 2 x 5 x 5 x 13: 2^1 x 5^2 x 13^1</p>
14 <p><strong>Step 2:</strong>Now we found out the prime factors of 650. The second step is to make pairs of those prime factors. Since 650 is not a perfect square, therefore the digits of the number can’t be grouped in pairs.</p>
14 <p><strong>Step 2:</strong>Now we found out the prime factors of 650. The second step is to make pairs of those prime factors. Since 650 is not a perfect square, therefore the digits of the number can’t be grouped in pairs.</p>
15 <p>Therefore, calculating 650 using prime factorization is impossible.</p>
15 <p>Therefore, calculating 650 using prime factorization is impossible.</p>
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18 <h2>Square Root of 650 by Long Division Method</h2>
17 <h2>Square Root of 650 by Long Division Method</h2>
19 <p>The long<a>division</a>method is particularly used for non-perfect square numbers. In this method, we should check the closest perfect square number for the given number. Let us now learn how to find the<a>square root</a>using the long division method, step by step.</p>
18 <p>The long<a>division</a>method is particularly used for non-perfect square numbers. In this method, we should check the closest perfect square number for the given number. Let us now learn how to find the<a>square root</a>using the long division method, step by step.</p>
20 <p><strong>Step 1:</strong>To begin with, we need to group the numbers from right to left. In the case of 650, we need to group it as 50 and 6.</p>
19 <p><strong>Step 1:</strong>To begin with, we need to group the numbers from right to left. In the case of 650, we need to group it as 50 and 6.</p>
21 <p><strong>Step 2:</strong>Now we need to find n whose square is<a>less than</a>or equal to 6. We can say n as ‘2’ because 2 x 2 = 4 is lesser than or equal to 6. Now the<a>quotient</a>is 2 after subtracting 6 - 4 the<a>remainder</a>is 2.</p>
20 <p><strong>Step 2:</strong>Now we need to find n whose square is<a>less than</a>or equal to 6. We can say n as ‘2’ because 2 x 2 = 4 is lesser than or equal to 6. Now the<a>quotient</a>is 2 after subtracting 6 - 4 the<a>remainder</a>is 2.</p>
22 <p><strong>Step 3:</strong>Now let us bring down 50 which is the new<a>dividend</a>. Add the old<a>divisor</a>with the same number 2 + 2, we get 4, which will be our new divisor.</p>
21 <p><strong>Step 3:</strong>Now let us bring down 50 which is the new<a>dividend</a>. Add the old<a>divisor</a>with the same number 2 + 2, we get 4, which will be our new divisor.</p>
23 <p><strong>Step 4:</strong>The new divisor will be 4n. We need to find the value of n such that 4n x n ≤ 250. Let us consider n as 5, now 45 x 5 = 225.</p>
22 <p><strong>Step 4:</strong>The new divisor will be 4n. We need to find the value of n such that 4n x n ≤ 250. Let us consider n as 5, now 45 x 5 = 225.</p>
24 <p><strong>Step 5:</strong>Subtract 250 from 225; the difference is 25, and the quotient is 25.</p>
23 <p><strong>Step 5:</strong>Subtract 250 from 225; the difference is 25, and the quotient is 25.</p>
25 <p><strong>Step 6:</strong>Since the dividend is less than the divisor, we need to add a decimal point. Adding the decimal point allows us to add two zeros to the dividend. Now the new dividend is 2500.</p>
24 <p><strong>Step 6:</strong>Since the dividend is less than the divisor, we need to add a decimal point. Adding the decimal point allows us to add two zeros to the dividend. Now the new dividend is 2500.</p>
26 <p><strong>Step 7:</strong>Now we need to find the new divisor. We find it by 510 x 5 = 2550, which is too large, so we try 509 x 4 = 2036.</p>
25 <p><strong>Step 7:</strong>Now we need to find the new divisor. We find it by 510 x 5 = 2550, which is too large, so we try 509 x 4 = 2036.</p>
27 <p><strong>Step 8:</strong>Subtracting 2036 from 2500 gives 464.</p>
26 <p><strong>Step 8:</strong>Subtracting 2036 from 2500 gives 464.</p>
28 <p><strong>Step 9:</strong>Now the quotient is 25.4. Step 10: Continue doing these steps until we get two numbers after the decimal point. Suppose if there is no decimal values continue till the remainder is zero.</p>
27 <p><strong>Step 9:</strong>Now the quotient is 25.4. Step 10: Continue doing these steps until we get two numbers after the decimal point. Suppose if there is no decimal values continue till the remainder is zero.</p>
29 <p>So the square root of √650 is approximately 25.495.</p>
28 <p>So the square root of √650 is approximately 25.495.</p>
30 <h2>Square Root of 650 by Approximation Method</h2>
29 <h2>Square Root of 650 by Approximation Method</h2>
31 <p>The approximation method is another method for finding square roots. It is an easy method to find the square root of a given number. Now let us learn how to find the square root of 650 using the approximation method.</p>
30 <p>The approximation method is another method for finding square roots. It is an easy method to find the square root of a given number. Now let us learn how to find the square root of 650 using the approximation method.</p>
32 <p><strong>Step 1:</strong>Now we have to find the closest perfect squares to √650. The smallest perfect square less than 650 is 625 and the largest perfect square<a>greater than</a>650 is 676. √650 falls somewhere between 25 and 26.</p>
31 <p><strong>Step 1:</strong>Now we have to find the closest perfect squares to √650. The smallest perfect square less than 650 is 625 and the largest perfect square<a>greater than</a>650 is 676. √650 falls somewhere between 25 and 26.</p>
33 <p><strong>Step 2:</strong>Now we need to apply the<a>formula</a>that is (Given number - smallest perfect square) / (Greater perfect square - smallest perfect square). Going by the formula (650 - 625) / (676 - 625) = 25/51 ≈ 0.49 Using the formula, we identified the<a>decimal</a>point of our square root. The next step is adding the value we got initially to the decimal number which is 25 + 0.49 = 25.49, so the square root of 650 is approximately 25.49.</p>
32 <p><strong>Step 2:</strong>Now we need to apply the<a>formula</a>that is (Given number - smallest perfect square) / (Greater perfect square - smallest perfect square). Going by the formula (650 - 625) / (676 - 625) = 25/51 ≈ 0.49 Using the formula, we identified the<a>decimal</a>point of our square root. The next step is adding the value we got initially to the decimal number which is 25 + 0.49 = 25.49, so the square root of 650 is approximately 25.49.</p>
34 <h2>Common Mistakes and How to Avoid Them in the Square Root of 650</h2>
33 <h2>Common Mistakes and How to Avoid Them in the Square Root of 650</h2>
35 <p>Students do make mistakes while finding the square root, like forgetting about the negative square root, skipping long division methods, etc. Now let us look at a few of those mistakes that students tend to make in detail.</p>
34 <p>Students do make mistakes while finding the square root, like forgetting about the negative square root, skipping long division methods, etc. Now let us look at a few of those mistakes that students tend to make in detail.</p>
 
35 + <h2>Download Worksheets</h2>
36 <h3>Problem 1</h3>
36 <h3>Problem 1</h3>
37 <p>Can you help Max find the area of a square box if its side length is given as √650?</p>
37 <p>Can you help Max find the area of a square box if its side length is given as √650?</p>
38 <p>Okay, lets begin</p>
38 <p>Okay, lets begin</p>
39 <p>The area of the square is approximately 650 square units.</p>
39 <p>The area of the square is approximately 650 square units.</p>
40 <h3>Explanation</h3>
40 <h3>Explanation</h3>
41 <p>The area of the square = side^2.</p>
41 <p>The area of the square = side^2.</p>
42 <p>The side length is given as √650.</p>
42 <p>The side length is given as √650.</p>
43 <p>Area of the square = (√650) x (√650) = 650.</p>
43 <p>Area of the square = (√650) x (√650) = 650.</p>
44 <p>Therefore, the area of the square box is approximately 650 square units.</p>
44 <p>Therefore, the area of the square box is approximately 650 square units.</p>
45 <p>Well explained 👍</p>
45 <p>Well explained 👍</p>
46 <h3>Problem 2</h3>
46 <h3>Problem 2</h3>
47 <p>A square-shaped building measuring 650 square feet is built; if each of the sides is √650, what will be the square feet of half of the building?</p>
47 <p>A square-shaped building measuring 650 square feet is built; if each of the sides is √650, what will be the square feet of half of the building?</p>
48 <p>Okay, lets begin</p>
48 <p>Okay, lets begin</p>
49 <p>325 square feet</p>
49 <p>325 square feet</p>
50 <h3>Explanation</h3>
50 <h3>Explanation</h3>
51 <p>We can just divide the given area by 2 as the building is square-shaped.</p>
51 <p>We can just divide the given area by 2 as the building is square-shaped.</p>
52 <p>Dividing 650 by 2 = we get 325.</p>
52 <p>Dividing 650 by 2 = we get 325.</p>
53 <p>So half of the building measures 325 square feet.</p>
53 <p>So half of the building measures 325 square feet.</p>
54 <p>Well explained 👍</p>
54 <p>Well explained 👍</p>
55 <h3>Problem 3</h3>
55 <h3>Problem 3</h3>
56 <p>Calculate √650 x 5.</p>
56 <p>Calculate √650 x 5.</p>
57 <p>Okay, lets begin</p>
57 <p>Okay, lets begin</p>
58 <p>Approximately 127.475</p>
58 <p>Approximately 127.475</p>
59 <h3>Explanation</h3>
59 <h3>Explanation</h3>
60 <p>The first step is to find the square root of 650 which is approximately 25.495, the second step is to multiply 25.495 with 5.</p>
60 <p>The first step is to find the square root of 650 which is approximately 25.495, the second step is to multiply 25.495 with 5.</p>
61 <p>So 25.495 x 5 ≈ 127.475.</p>
61 <p>So 25.495 x 5 ≈ 127.475.</p>
62 <p>Well explained 👍</p>
62 <p>Well explained 👍</p>
63 <h3>Problem 4</h3>
63 <h3>Problem 4</h3>
64 <p>What will be the square root of (650 + 25)?</p>
64 <p>What will be the square root of (650 + 25)?</p>
65 <p>Okay, lets begin</p>
65 <p>Okay, lets begin</p>
66 <p>The square root is approximately 26.</p>
66 <p>The square root is approximately 26.</p>
67 <h3>Explanation</h3>
67 <h3>Explanation</h3>
68 <p>To find the square root, we need to find the sum of (650 + 25).</p>
68 <p>To find the square root, we need to find the sum of (650 + 25).</p>
69 <p>650 + 25 = 675, and then √675 ≈ 25.98.</p>
69 <p>650 + 25 = 675, and then √675 ≈ 25.98.</p>
70 <p>Therefore, the square root of (650 + 25) is approximately 26.</p>
70 <p>Therefore, the square root of (650 + 25) is approximately 26.</p>
71 <p>Well explained 👍</p>
71 <p>Well explained 👍</p>
72 <h3>Problem 5</h3>
72 <h3>Problem 5</h3>
73 <p>Find the perimeter of the rectangle if its length ‘l’ is √650 units and the width ‘w’ is 38 units.</p>
73 <p>Find the perimeter of the rectangle if its length ‘l’ is √650 units and the width ‘w’ is 38 units.</p>
74 <p>Okay, lets begin</p>
74 <p>Okay, lets begin</p>
75 <p>We find the perimeter of the rectangle to be approximately 126.99 units.</p>
75 <p>We find the perimeter of the rectangle to be approximately 126.99 units.</p>
76 <h3>Explanation</h3>
76 <h3>Explanation</h3>
77 <p>Perimeter of the rectangle = 2 × (length + width)</p>
77 <p>Perimeter of the rectangle = 2 × (length + width)</p>
78 <p>Perimeter = 2 × (√650 + 38)</p>
78 <p>Perimeter = 2 × (√650 + 38)</p>
79 <p>= 2 × (25.495 + 38)</p>
79 <p>= 2 × (25.495 + 38)</p>
80 <p>= 2 × 63.495</p>
80 <p>= 2 × 63.495</p>
81 <p>≈ 126.99 units.</p>
81 <p>≈ 126.99 units.</p>
82 <p>Well explained 👍</p>
82 <p>Well explained 👍</p>
83 <h2>FAQ on Square Root of 650</h2>
83 <h2>FAQ on Square Root of 650</h2>
84 <h3>1.What is √650 in its simplest form?</h3>
84 <h3>1.What is √650 in its simplest form?</h3>
85 <p>The prime factorization of 650 is 2 x 5 x 5 x 13, so the simplest form of √650 = √(2 x 5^2 x 13).</p>
85 <p>The prime factorization of 650 is 2 x 5 x 5 x 13, so the simplest form of √650 = √(2 x 5^2 x 13).</p>
86 <h3>2.Mention the factors of 650.</h3>
86 <h3>2.Mention the factors of 650.</h3>
87 <p>Factors of 650 are 1, 2, 5, 10, 13, 25, 26, 50, 65, 130, 325, and 650.</p>
87 <p>Factors of 650 are 1, 2, 5, 10, 13, 25, 26, 50, 65, 130, 325, and 650.</p>
88 <h3>3.Calculate the square of 650.</h3>
88 <h3>3.Calculate the square of 650.</h3>
89 <p>We get the square of 650 by multiplying the number by itself, that is 650 x 650 = 422500.</p>
89 <p>We get the square of 650 by multiplying the number by itself, that is 650 x 650 = 422500.</p>
90 <h3>4.Is 650 a prime number?</h3>
90 <h3>4.Is 650 a prime number?</h3>
91 <h3>5.650 is divisible by?</h3>
91 <h3>5.650 is divisible by?</h3>
92 <p>650 has many factors; those are 1, 2, 5, 10, 13, 25, 26, 50, 65, 130, 325, and 650.</p>
92 <p>650 has many factors; those are 1, 2, 5, 10, 13, 25, 26, 50, 65, 130, 325, and 650.</p>
93 <h2>Important Glossaries for the Square Root of 650</h2>
93 <h2>Important Glossaries for the Square Root of 650</h2>
94 <ul><li><strong>Square root:</strong>A square root is the inverse of a square. For example: 5^2 = 25, and the inverse of the square is the square root, that is √25 = 5. </li>
94 <ul><li><strong>Square root:</strong>A square root is the inverse of a square. For example: 5^2 = 25, and the inverse of the square is the square root, that is √25 = 5. </li>
95 <li><strong>Irrational number:</strong>An irrational number is a number that cannot be written in the form of p/q, where q is not equal to zero and p and q are integers. </li>
95 <li><strong>Irrational number:</strong>An irrational number is a number that cannot be written in the form of p/q, where q is not equal to zero and p and q are integers. </li>
96 <li><strong>Principal square root:</strong>A number has both positive and negative square roots; however, it is always the positive square root that has more prominence due to its uses in the real world. That is the reason it is also known as a principal square root. </li>
96 <li><strong>Principal square root:</strong>A number has both positive and negative square roots; however, it is always the positive square root that has more prominence due to its uses in the real world. That is the reason it is also known as a principal square root. </li>
97 <li><strong>Prime factorization:</strong>The process of expressing a number as the product of its prime factors. For example, the prime factorization of 18 is 2 x 3 x 3. </li>
97 <li><strong>Prime factorization:</strong>The process of expressing a number as the product of its prime factors. For example, the prime factorization of 18 is 2 x 3 x 3. </li>
98 <li><strong>Long division method:</strong>A method used to find the square root of non-perfect squares through repeated division and subtraction, yielding increasingly accurate approximations.</li>
98 <li><strong>Long division method:</strong>A method used to find the square root of non-perfect squares through repeated division and subtraction, yielding increasingly accurate approximations.</li>
99 </ul><p>What Is Algebra? 🧮 | Simple Explanation with 🎯 Cool Examples for Kids | ✨BrightCHAMPS Math</p>
99 </ul><p>What Is Algebra? 🧮 | Simple Explanation with 🎯 Cool Examples for Kids | ✨BrightCHAMPS Math</p>
100 <p>▶</p>
100 <p>▶</p>
101 <h2>Jaskaran Singh Saluja</h2>
101 <h2>Jaskaran Singh Saluja</h2>
102 <h3>About the Author</h3>
102 <h3>About the Author</h3>
103 <p>Jaskaran Singh Saluja is a math wizard with nearly three years of experience as a math teacher. His expertise is in algebra, so he can make algebra classes interesting by turning tricky equations into simple puzzles.</p>
103 <p>Jaskaran Singh Saluja is a math wizard with nearly three years of experience as a math teacher. His expertise is in algebra, so he can make algebra classes interesting by turning tricky equations into simple puzzles.</p>
104 <h3>Fun Fact</h3>
104 <h3>Fun Fact</h3>
105 <p>: He loves to play the quiz with kids through algebra to make kids love it.</p>
105 <p>: He loves to play the quiz with kids through algebra to make kids love it.</p>