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2 <p>Last updated on<strong>November 27, 2025</strong></p>
2 <p>Last updated on<strong>November 27, 2025</strong></p>
3 <p>The multiplication rule of probability is a fundamental concept of probability theory. It is the relationship between two or more events that occur together. In this topic, we are going to talk about the multiplication rule of probability and where we use it.</p>
3 <p>The multiplication rule of probability is a fundamental concept of probability theory. It is the relationship between two or more events that occur together. In this topic, we are going to talk about the multiplication rule of probability and where we use it.</p>
4 <h2>What is the Multiplication Rule of Probability?</h2>
4 <h2>What is the Multiplication Rule of Probability?</h2>
5 <p>The Multiplication rule<a>of</a><a>probability</a>determines the likelihood of two or more events occurring together, which is often signaled by the word "AND" in a problem statement. When events are independent-meaning the result of one does not affect the other-the Multiplication rule probability<a>formula</a>is straightforward: you simply multiply the probability of the first event by the probability of the second (\(P(A) \times P(B)\)). This fundamental concept is frequently referred to as the Multiplication law of probability or the Probability rule<a>multiplication</a>in introductory<a>statistics</a>.</p>
5 <p>The Multiplication rule<a>of</a><a>probability</a>determines the likelihood of two or more events occurring together, which is often signaled by the word "AND" in a problem statement. When events are independent-meaning the result of one does not affect the other-the Multiplication rule probability<a>formula</a>is straightforward: you simply multiply the probability of the first event by the probability of the second (\(P(A) \times P(B)\)). This fundamental concept is frequently referred to as the Multiplication law of probability or the Probability rule<a>multiplication</a>in introductory<a>statistics</a>.</p>
6 <p>However, when the outcome of the first event impacts the second (such as drawing a card without putting it back), you must apply the General Multiplication rule of probability for<a>dependent events</a>. In this scenario, the Multiplication rule for probability adjusts to use<a>conditional probability</a>: \(P(A) \times P(B|A)\). Whether you encounter it as the Rule of multiplication in probability, the Multiplication rule in probability, or simply "What is the multiplication rule," the core principle remains the same: multiply the probabilities, but ensure you account for any changes in the sample space if the events are dependent.</p>
6 <p>However, when the outcome of the first event impacts the second (such as drawing a card without putting it back), you must apply the General Multiplication rule of probability for<a>dependent events</a>. In this scenario, the Multiplication rule for probability adjusts to use<a>conditional probability</a>: \(P(A) \times P(B|A)\). Whether you encounter it as the Rule of multiplication in probability, the Multiplication rule in probability, or simply "What is the multiplication rule," the core principle remains the same: multiply the probabilities, but ensure you account for any changes in the sample space if the events are dependent.</p>
7 <h2>Multiplication Rule of Probability Formula</h2>
7 <h2>Multiplication Rule of Probability Formula</h2>
8 <p>Here are the two formulas for the probability multiplication rule, depending on whether the events affect each other. This rule is specifically used to calculate the probability of two events happening together (A and B), either simultaneously or one after the other.</p>
8 <p>Here are the two formulas for the probability multiplication rule, depending on whether the events affect each other. This rule is specifically used to calculate the probability of two events happening together (A and B), either simultaneously or one after the other.</p>
9 <h3><strong>For Independent Events</strong></h3>
9 <h3><strong>For Independent Events</strong></h3>
10 <p>Use this formula when the outcome of the first event does not change the probability of the second (e.g., flipping a coin twice).</p>
10 <p>Use this formula when the outcome of the first event does not change the probability of the second (e.g., flipping a coin twice).</p>
11 <p>\(P(A \cap B) = P(A) \times P(B)\)</p>
11 <p>\(P(A \cap B) = P(A) \times P(B)\)</p>
12 <ul><li>\(P(A \cap B)\): The probability of Event A and Event B both happening.</li>
12 <ul><li>\(P(A \cap B)\): The probability of Event A and Event B both happening.</li>
13 <li>P(A): The probability of Event A.</li>
13 <li>P(A): The probability of Event A.</li>
14 <li>P(B): The probability of Event B.</li>
14 <li>P(B): The probability of Event B.</li>
15 </ul><h3><strong>For Dependent Events (Conditional)</strong></h3>
15 </ul><h3><strong>For Dependent Events (Conditional)</strong></h3>
16 <p>Use this formula when the first event changes the available options for the second (e.g., drawing a card and not putting it back).</p>
16 <p>Use this formula when the first event changes the available options for the second (e.g., drawing a card and not putting it back).</p>
17 <p>\(P(A \cap B) = P(A) \times P(B|A)\)</p>
17 <p>\(P(A \cap B) = P(A) \times P(B|A)\)</p>
18 <ul><li>\(P(B|A)\): The conditional probability of Event B, given that Event A has already occurred.</li>
18 <ul><li>\(P(B|A)\): The conditional probability of Event B, given that Event A has already occurred.</li>
19 </ul><h2>Proof of the Multiplication Rule of Probability</h2>
19 </ul><h2>Proof of the Multiplication Rule of Probability</h2>
20 <p>The proof for the Multiplication Rule is derived directly from the definition of Conditional Probability.</p>
20 <p>The proof for the Multiplication Rule is derived directly from the definition of Conditional Probability.</p>
21 <p>The formula for the conditional probability of Event B occurring given that Event A has occurred is defined as the probability of both happening divided by the probability of the condition (A):</p>
21 <p>The formula for the conditional probability of Event B occurring given that Event A has occurred is defined as the probability of both happening divided by the probability of the condition (A):</p>
22 <p>\(P(B|A) = \frac{P(A \cap B)}{P(A)}\)</p>
22 <p>\(P(B|A) = \frac{P(A \cap B)}{P(A)}\)</p>
23 <p>To find the probability of both events happening (\(A \cap B\)), we simply rearrange this formula to isolate the intersection.</p>
23 <p>To find the probability of both events happening (\(A \cap B\)), we simply rearrange this formula to isolate the intersection.</p>
24 <p><strong>Step 1:</strong>Multiply both sides of the<a>equation</a>by P(A) (assuming P(A) &gt; 0).</p>
24 <p><strong>Step 1:</strong>Multiply both sides of the<a>equation</a>by P(A) (assuming P(A) &gt; 0).</p>
25 <p>\(P(A) \times P(B|A) = P(A) \times \frac{P(A \cap B)}{P(A)}\)</p>
25 <p>\(P(A) \times P(B|A) = P(A) \times \frac{P(A \cap B)}{P(A)}\)</p>
26 <p><strong>Step 2:</strong>Cancel out P(A) on the right side.</p>
26 <p><strong>Step 2:</strong>Cancel out P(A) on the right side.</p>
27 <p>\(P(A) \times P(B|A) = P(A \cap B)\)</p>
27 <p>\(P(A) \times P(B|A) = P(A \cap B)\)</p>
28 <p><strong>Step 3:</strong>Rearrange to get the standard Multiplication Rule.</p>
28 <p><strong>Step 3:</strong>Rearrange to get the standard Multiplication Rule.</p>
29 <p>\(P(A \cap B) = P(A) \times P(B|A)\)</p>
29 <p>\(P(A \cap B) = P(A) \times P(B|A)\)</p>
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32 <h2>How to Use the Multiplication Rule of Probability</h2>
31 <h2>How to Use the Multiplication Rule of Probability</h2>
33 <p>Think of the Multiplication Rule as the "AND" rule. We use it whenever we want to know the probability of two things happening together (Event A and Event B).</p>
32 <p>Think of the Multiplication Rule as the "AND" rule. We use it whenever we want to know the probability of two things happening together (Event A and Event B).</p>
34 <p>The trick isn't the<a>math</a>itself (which is just multiplying); the trick is asking yourself one simple<a>question</a>before you start: "Did the first event change the situation for the second event?" Your answer decides which path you take.</p>
33 <p>The trick isn't the<a>math</a>itself (which is just multiplying); the trick is asking yourself one simple<a>question</a>before you start: "Did the first event change the situation for the second event?" Your answer decides which path you take.</p>
35 <h3><strong>1. Independent Events (The "Clean Slate" Scenario)</strong></h3>
34 <h3><strong>1. Independent Events (The "Clean Slate" Scenario)</strong></h3>
36 <p>If the events are independent, they don't care about each other. The result of the first event doesn't change the odds of the second.</p>
35 <p>If the events are independent, they don't care about each other. The result of the first event doesn't change the odds of the second.</p>
37 <ul><li><strong>Scenario:</strong>Flipping a coin. The coin has no memory. Even if you just flipped Heads, the chance of flipping Heads again is still 50/50.</li>
36 <ul><li><strong>Scenario:</strong>Flipping a coin. The coin has no memory. Even if you just flipped Heads, the chance of flipping Heads again is still 50/50.</li>
38 <li><strong>The Formula:</strong><p>\(P(A \text{ and } B) = P(A) \times P(B)\)</p>
37 <li><strong>The Formula:</strong><p>\(P(A \text{ and } B) = P(A) \times P(B)\)</p>
39 </li>
38 </li>
40 </ul><p><strong>Example:</strong>Imagine you flip a coin and roll a standard die at the same time. You want to get "Heads" and a "5".</p>
39 </ul><p><strong>Example:</strong>Imagine you flip a coin and roll a standard die at the same time. You want to get "Heads" and a "5".</p>
41 <ul><li>The Coin: Has a \(1\over 2\) chance of Heads.</li>
40 <ul><li>The Coin: Has a \(1\over 2\) chance of Heads.</li>
42 <li>The Die: Has a \(1\over 6\) chance of rolling a 5.</li>
41 <li>The Die: Has a \(1\over 6\) chance of rolling a 5.</li>
43 <li>Since the coin doesn't affect the die, just multiply straight across: \( {1\over 2} \times {1\over 6} = {1\over 12}\)</li>
42 <li>Since the coin doesn't affect the die, just multiply straight across: \( {1\over 2} \times {1\over 6} = {1\over 12}\)</li>
44 </ul><h3><strong>2. Dependent Events (The "No Going Back" Scenario)</strong></h3>
43 </ul><h3><strong>2. Dependent Events (The "No Going Back" Scenario)</strong></h3>
45 <p>If the events are dependent, the first action changes the universe slightly for the second action. This usually happens when you take something away and don't put it back (without replacement).</p>
44 <p>If the events are dependent, the first action changes the universe slightly for the second action. This usually happens when you take something away and don't put it back (without replacement).</p>
46 <ul><li><strong>Scenario:</strong>Eating chocolates from a box. Once you eat a caramel one, there is one less caramel chocolate and one less chocolate total in the box. The odds for the next pick have shifted.</li>
45 <ul><li><strong>Scenario:</strong>Eating chocolates from a box. Once you eat a caramel one, there is one less caramel chocolate and one less chocolate total in the box. The odds for the next pick have shifted.</li>
47 <li><strong>The Formula:</strong><p>\(P(A \text{ and } B) = P(A) \times P(B|A)\)</p>
46 <li><strong>The Formula:</strong><p>\(P(A \text{ and } B) = P(A) \times P(B|A)\)</p>
48 </li>
47 </li>
49 </ul><p>(Don't let the notation scare you. P(B|A) just means "The probability of B, considering A is already gone.")</p>
48 </ul><p>(Don't let the notation scare you. P(B|A) just means "The probability of B, considering A is already gone.")</p>
50 <p><strong>Example:</strong>You have a bag with 2 Orange marbles and 2 Purple marbles. You grab one, put it in your pocket, and then grab another. What are the odds of getting two Orange marbles in a row?</p>
49 <p><strong>Example:</strong>You have a bag with 2 Orange marbles and 2 Purple marbles. You grab one, put it in your pocket, and then grab another. What are the odds of getting two Orange marbles in a row?</p>
51 <ul><li><strong>First Draw:</strong>There are 4 marbles, and 2 are Orange. Probability: \(2\over 4\) (or \(1\over 2\))</li>
50 <ul><li><strong>First Draw:</strong>There are 4 marbles, and 2 are Orange. Probability: \(2\over 4\) (or \(1\over 2\))</li>
52 <li><strong>Second Draw:</strong>Now the situation has changed. You have one Orange marble in your pocket. That means there are only 3 marbles left in the bag, and only 1 is Orange. Probability: \(1\over 3\)</li>
51 <li><strong>Second Draw:</strong>Now the situation has changed. You have one Orange marble in your pocket. That means there are only 3 marbles left in the bag, and only 1 is Orange. Probability: \(1\over 3\)</li>
53 <li>Multiply the first probability by the new probability: \({1\over 2} \times {1\over 3} = {1\over 6}\)</li>
52 <li>Multiply the first probability by the new probability: \({1\over 2} \times {1\over 3} = {1\over 6}\)</li>
54 </ul><h2>Tips and Tricks to Master Multiplication Rule of Probability</h2>
53 </ul><h2>Tips and Tricks to Master Multiplication Rule of Probability</h2>
55 <p>Multiplication Rule of Probability is a complex mathematical concept. In this section, we will discuss some tips and tricks that can be very helpful. </p>
54 <p>Multiplication Rule of Probability is a complex mathematical concept. In this section, we will discuss some tips and tricks that can be very helpful. </p>
56 <ul><li><strong>Convert percentages to<a>decimals</a>:</strong>When working with percentages, convert them to decimals before multiplying (e.g., 40% → 0.4). </li>
55 <ul><li><strong>Convert percentages to<a>decimals</a>:</strong>When working with percentages, convert them to decimals before multiplying (e.g., 40% → 0.4). </li>
57 <li><strong>Simplify step-by-step:</strong>When<a>multiple</a>events are involved, multiply two probabilities at a time to reduce calculation mistakes. </li>
56 <li><strong>Simplify step-by-step:</strong>When<a>multiple</a>events are involved, multiply two probabilities at a time to reduce calculation mistakes. </li>
58 <li><strong>Double-check event independence:</strong>Never assume events are independent unless explicitly mentioned. Misunderstanding this is a common exam error. </li>
57 <li><strong>Double-check event independence:</strong>Never assume events are independent unless explicitly mentioned. Misunderstanding this is a common exam error. </li>
59 <li><strong>Cross-verify with total probability:</strong>After calculating joint probabilities, ensure the total probability of all possible outcomes adds up to 1. </li>
58 <li><strong>Cross-verify with total probability:</strong>After calculating joint probabilities, ensure the total probability of all possible outcomes adds up to 1. </li>
60 <li><strong>Practice word problems frequently:</strong>The more scenarios you solve cards, dice, weather, or business cases, the better your understanding of applying the rule correctly.</li>
59 <li><strong>Practice word problems frequently:</strong>The more scenarios you solve cards, dice, weather, or business cases, the better your understanding of applying the rule correctly.</li>
61 </ul><h2>Common Mistakes and How to Avoid Them in Multiplication Rule of Probability</h2>
60 </ul><h2>Common Mistakes and How to Avoid Them in Multiplication Rule of Probability</h2>
62 <p>Students might make mistakes when learning about the multiplication rule of probability. So here are a few mistakes that students make and ways to avoid them:</p>
61 <p>Students might make mistakes when learning about the multiplication rule of probability. So here are a few mistakes that students make and ways to avoid them:</p>
63 <h2>Real-Life Applications on Multiplication Rule of Probability</h2>
62 <h2>Real-Life Applications on Multiplication Rule of Probability</h2>
64 <p>There are many uses of the multiplication rule of probability. Let us now see the uses and applications of the multiplication rule in different fields: </p>
63 <p>There are many uses of the multiplication rule of probability. Let us now see the uses and applications of the multiplication rule in different fields: </p>
65 <ul><li><strong>Healthcare:</strong>Hospitals and clinics use the multiplication rule to calculate the probability of a patient having any particular disease based on multiple results. </li>
64 <ul><li><strong>Healthcare:</strong>Hospitals and clinics use the multiplication rule to calculate the probability of a patient having any particular disease based on multiple results. </li>
66 <li><strong>Weather forecast:</strong>To predict the likelihood of complex weather events, meteorologists use the multiplication rule of probability. This can help show whether there is going to be high humidity due to a storm occurring. </li>
65 <li><strong>Weather forecast:</strong>To predict the likelihood of complex weather events, meteorologists use the multiplication rule of probability. This can help show whether there is going to be high humidity due to a storm occurring. </li>
67 <li><strong>Marketing campaigns:</strong>The multiplication rule helps estimate the overall success<a>rate</a>of a campaign by taking into consideration the probabilities of multiple independent<a>factors</a>, such as audience engagement, advertisements, etc. </li>
66 <li><strong>Marketing campaigns:</strong>The multiplication rule helps estimate the overall success<a>rate</a>of a campaign by taking into consideration the probabilities of multiple independent<a>factors</a>, such as audience engagement, advertisements, etc. </li>
68 <li><strong>Finance and investment:</strong>Banks and investors use the multiplication rule to calculate the probability of multiple market factors occurring together, such as stock growth and interest rate changes, to assess risks and returns. </li>
67 <li><strong>Finance and investment:</strong>Banks and investors use the multiplication rule to calculate the probability of multiple market factors occurring together, such as stock growth and interest rate changes, to assess risks and returns. </li>
69 <li><strong>Manufacturing and quality Control:</strong>Industries use it to find the probability of multiple machines or components functioning correctly at the same time, ensuring the final<a>product</a>meets quality standards.</li>
68 <li><strong>Manufacturing and quality Control:</strong>Industries use it to find the probability of multiple machines or components functioning correctly at the same time, ensuring the final<a>product</a>meets quality standards.</li>
70 </ul><h3>Problem 1</h3>
69 </ul><h3>Problem 1</h3>
71 <p>A deck has 52 cards. What is the probability of drawing two aces in a row without replacement?</p>
70 <p>A deck has 52 cards. What is the probability of drawing two aces in a row without replacement?</p>
72 <p>Okay, lets begin</p>
71 <p>Okay, lets begin</p>
73 <p>0.0045</p>
72 <p>0.0045</p>
74 <h3>Explanation</h3>
73 <h3>Explanation</h3>
75 <p> P(Ace1 ∩ Ace2) = 452 × 351</p>
74 <p> P(Ace1 ∩ Ace2) = 452 × 351</p>
76 <p>= 122652</p>
75 <p>= 122652</p>
77 <p>= 0.0045</p>
76 <p>= 0.0045</p>
78 <p><strong>Step 1:</strong>Probability of drawing the first ace = 4 / 52</p>
77 <p><strong>Step 1:</strong>Probability of drawing the first ace = 4 / 52</p>
79 <p><strong>Step 2:</strong>Since one ace has been removed, the probability of drawing a second ace = 3 / 51 .</p>
78 <p><strong>Step 2:</strong>Since one ace has been removed, the probability of drawing a second ace = 3 / 51 .</p>
80 <p><strong>Step 3:</strong>Multiply both probabilities: 4 / 52 × 3 / 51</p>
79 <p><strong>Step 3:</strong>Multiply both probabilities: 4 / 52 × 3 / 51</p>
81 <p>Well explained 👍</p>
80 <p>Well explained 👍</p>
82 <h3>Problem 2</h3>
81 <h3>Problem 2</h3>
83 <p>What is the probability of getting two heads when flipping two fair coins?</p>
82 <p>What is the probability of getting two heads when flipping two fair coins?</p>
84 <p>Okay, lets begin</p>
83 <p>Okay, lets begin</p>
85 <p>1/4</p>
84 <p>1/4</p>
86 <h3>Explanation</h3>
85 <h3>Explanation</h3>
87 <p>P(H1 ∩ H2) = 1 / 2 × 1 / 2 = 1 / 4</p>
86 <p>P(H1 ∩ H2) = 1 / 2 × 1 / 2 = 1 / 4</p>
88 <p><strong>Step 1:</strong>Probability of getting heads on the first flip = 1 / 2</p>
87 <p><strong>Step 1:</strong>Probability of getting heads on the first flip = 1 / 2</p>
89 <p><strong>Step 2:</strong>Probability of getting heads on the second flip = 1 / 2</p>
88 <p><strong>Step 2:</strong>Probability of getting heads on the second flip = 1 / 2</p>
90 <p><strong>Step 3:</strong>Multiply both: 1 / 2 × 1 / 2 </p>
89 <p><strong>Step 3:</strong>Multiply both: 1 / 2 × 1 / 2 </p>
91 <p>Well explained 👍</p>
90 <p>Well explained 👍</p>
92 <h3>Problem 3</h3>
91 <h3>Problem 3</h3>
93 <p>A bag has 5 red and 10 blue marbles. If you pick two marbles with replacement, what is the probability of getting two red ones?</p>
92 <p>A bag has 5 red and 10 blue marbles. If you pick two marbles with replacement, what is the probability of getting two red ones?</p>
94 <p>Okay, lets begin</p>
93 <p>Okay, lets begin</p>
95 <p>1/9</p>
94 <p>1/9</p>
96 <h3>Explanation</h3>
95 <h3>Explanation</h3>
97 <p>P(R1 ∩ R2) = 5 / 15 × 5 / 15 = 1 / 9</p>
96 <p>P(R1 ∩ R2) = 5 / 15 × 5 / 15 = 1 / 9</p>
98 <p><strong>Step 1:</strong>Probability of first red = 5 / 15</p>
97 <p><strong>Step 1:</strong>Probability of first red = 5 / 15</p>
99 <p><strong>Step 2:</strong>Since replacement occurs, second red = 5 / 15.</p>
98 <p><strong>Step 2:</strong>Since replacement occurs, second red = 5 / 15.</p>
100 <p><strong>Step 3:</strong>Multiply 5 / 15 × 5 / 15</p>
99 <p><strong>Step 3:</strong>Multiply 5 / 15 × 5 / 15</p>
101 <p>Well explained 👍</p>
100 <p>Well explained 👍</p>
102 <h3>Problem 4</h3>
101 <h3>Problem 4</h3>
103 <p>A group has 6 females and 4 males. What is the probability of randomly selecting two females?</p>
102 <p>A group has 6 females and 4 males. What is the probability of randomly selecting two females?</p>
104 <p>Okay, lets begin</p>
103 <p>Okay, lets begin</p>
105 <p>1/3</p>
104 <p>1/3</p>
106 <h3>Explanation</h3>
105 <h3>Explanation</h3>
107 <p> P(F1 ∩ F2) = 6/10 × 5/9 = 30/90 =1/3 </p>
106 <p> P(F1 ∩ F2) = 6/10 × 5/9 = 30/90 =1/3 </p>
108 <p><strong>Step 1:</strong>Probability of first female = 6/10</p>
107 <p><strong>Step 1:</strong>Probability of first female = 6/10</p>
109 <p><strong>Step 2:</strong>Probability of the second female (after one is removed) = 5/9</p>
108 <p><strong>Step 2:</strong>Probability of the second female (after one is removed) = 5/9</p>
110 <p><strong>Step 3:</strong>Multiply: 6/10 × 5/9</p>
109 <p><strong>Step 3:</strong>Multiply: 6/10 × 5/9</p>
111 <p>Well explained 👍</p>
110 <p>Well explained 👍</p>
112 <h3>Problem 5</h3>
111 <h3>Problem 5</h3>
113 <p>Machine A has a failure probability of 0.1, and Machine B has 0.2. What is the probability that both fail?</p>
112 <p>Machine A has a failure probability of 0.1, and Machine B has 0.2. What is the probability that both fail?</p>
114 <p>Okay, lets begin</p>
113 <p>Okay, lets begin</p>
115 <p> 0.02</p>
114 <p> 0.02</p>
116 <h3>Explanation</h3>
115 <h3>Explanation</h3>
117 <p> P(A ∩ B) = 0.1 × 0.2 = 0.02</p>
116 <p> P(A ∩ B) = 0.1 × 0.2 = 0.02</p>
118 <p><strong>Step 1:</strong>Probability of failure of A = 0.1</p>
117 <p><strong>Step 1:</strong>Probability of failure of A = 0.1</p>
119 <p><strong>Step 2:</strong>Probability of failure of B = 0.2</p>
118 <p><strong>Step 2:</strong>Probability of failure of B = 0.2</p>
120 <p><strong>Step 3:</strong>Multiply: 0.1 × 0.2</p>
119 <p><strong>Step 3:</strong>Multiply: 0.1 × 0.2</p>
121 <p>Well explained 👍</p>
120 <p>Well explained 👍</p>
122 <h3>Problem 6</h3>
121 <h3>Problem 6</h3>
123 <p>A factory makes 5% defective items. What is the probability of picking two defective ones?</p>
122 <p>A factory makes 5% defective items. What is the probability of picking two defective ones?</p>
124 <p>Okay, lets begin</p>
123 <p>Okay, lets begin</p>
125 <p>0.0025</p>
124 <p>0.0025</p>
126 <h3>Explanation</h3>
125 <h3>Explanation</h3>
127 <p>P(D1 ∩ D2) = 0.05 × 0.05 = 0.0025</p>
126 <p>P(D1 ∩ D2) = 0.05 × 0.05 = 0.0025</p>
128 <p><strong>Step 1:</strong>Probability of first defective = 0.05</p>
127 <p><strong>Step 1:</strong>Probability of first defective = 0.05</p>
129 <p><strong>Step 2:</strong>Probability of second defective = 0.05</p>
128 <p><strong>Step 2:</strong>Probability of second defective = 0.05</p>
130 <p><strong>Step 3:</strong>Multiply: 0.05 × 0 .05</p>
129 <p><strong>Step 3:</strong>Multiply: 0.05 × 0 .05</p>
131 <p>Well explained 👍</p>
130 <p>Well explained 👍</p>
132 <h2>FAQs on Multiplication Rule of Probability</h2>
131 <h2>FAQs on Multiplication Rule of Probability</h2>
133 <h3>1.What is the multiplication rule of probability?</h3>
132 <h3>1.What is the multiplication rule of probability?</h3>
134 <p>The multiplication rule is the probability of two events A and B occurring together is:</p>
133 <p>The multiplication rule is the probability of two events A and B occurring together is:</p>
135 <p>If the event is independent: P (A ∩ B) = P(A) × P(B)</p>
134 <p>If the event is independent: P (A ∩ B) = P(A) × P(B)</p>
136 <p>If the event is dependent: P (A ∩ B) = P(A) × P(B|A)</p>
135 <p>If the event is dependent: P (A ∩ B) = P(A) × P(B|A)</p>
137 <h3>2.How can we determine that two events are independent?</h3>
136 <h3>2.How can we determine that two events are independent?</h3>
138 <p> If the outcome of one event does not change the outcome of the second event, they are termed as independent events.</p>
137 <p> If the outcome of one event does not change the outcome of the second event, they are termed as independent events.</p>
139 <h3>3.Can the multiplication rule be used for more than two events?</h3>
138 <h3>3.Can the multiplication rule be used for more than two events?</h3>
140 <p> Yes, the multiplication rule can be used for more than two events.</p>
139 <p> Yes, the multiplication rule can be used for more than two events.</p>
141 <p>If events A, B, and C are independent then:</p>
140 <p>If events A, B, and C are independent then:</p>
142 <p>P (A ∩ B ∩ C) = P(A) × P(B) × P(C)</p>
141 <p>P (A ∩ B ∩ C) = P(A) × P(B) × P(C)</p>
143 <h3>4.What happens if both events A and B are mutually exclusive?</h3>
142 <h3>4.What happens if both events A and B are mutually exclusive?</h3>
144 <p>If events A and B are mutually exclusive, then the intersection of these two events is 0. P(A ∩ B) = 0.</p>
143 <p>If events A and B are mutually exclusive, then the intersection of these two events is 0. P(A ∩ B) = 0.</p>
145 <h3>5.Can the probability of the events be greater than 1?</h3>
144 <h3>5.Can the probability of the events be greater than 1?</h3>
146 <p> No, the maximum probability of events is 1. If you get a<a>number</a>greater than 1, then there is an error in the calculation.</p>
145 <p> No, the maximum probability of events is 1. If you get a<a>number</a>greater than 1, then there is an error in the calculation.</p>
147 <h2>Jaipreet Kour Wazir</h2>
146 <h2>Jaipreet Kour Wazir</h2>
148 <h3>About the Author</h3>
147 <h3>About the Author</h3>
149 <p>Jaipreet Kour Wazir is a data wizard with over 5 years of expertise in simplifying complex data concepts. From crunching numbers to crafting insightful visualizations, she turns raw data into compelling stories. Her journey from analytics to education ref</p>
148 <p>Jaipreet Kour Wazir is a data wizard with over 5 years of expertise in simplifying complex data concepts. From crunching numbers to crafting insightful visualizations, she turns raw data into compelling stories. Her journey from analytics to education ref</p>
150 <h3>Fun Fact</h3>
149 <h3>Fun Fact</h3>
151 <p>: She compares datasets to puzzle games-the more you play with them, the clearer the picture becomes!</p>
150 <p>: She compares datasets to puzzle games-the more you play with them, the clearer the picture becomes!</p>