2 added
2 removed
Original
2026-01-01
Modified
2026-02-28
1
-
<p>508 Learners</p>
1
+
<p>554 Learners</p>
2
<p>Last updated on<strong>August 5, 2025</strong></p>
2
<p>Last updated on<strong>August 5, 2025</strong></p>
3
<p>The cube root of Unity (or one) are the values which, when multiplied together, gives the original number Unity. The Cube Root of Unity is represented by ∛1, which actually have three roots→ 1,𝛚, 𝛚², which on multiplication together gives “1” as a product. 1×𝛚×𝛚²=1.</p>
3
<p>The cube root of Unity (or one) are the values which, when multiplied together, gives the original number Unity. The Cube Root of Unity is represented by ∛1, which actually have three roots→ 1,𝛚, 𝛚², which on multiplication together gives “1” as a product. 1×𝛚×𝛚²=1.</p>
4
<h2>What Is the Cube Root of Unity?</h2>
4
<h2>What Is the Cube Root of Unity?</h2>
5
<p>What Is Algebra? 🧮 | Simple Explanation with 🎯 Cool Examples for Kids | ✨BrightCHAMPS Math</p>
5
<p>What Is Algebra? 🧮 | Simple Explanation with 🎯 Cool Examples for Kids | ✨BrightCHAMPS Math</p>
6
<p>▶</p>
6
<p>▶</p>
7
<p>As mentioned above, the<a>cube</a>root of Unity are 1,𝛚, 𝛚², where 1 is a real root, 𝛚 and 𝛚² are the imaginary roots. The essential features or properties of the cube root of Unity are:</p>
7
<p>As mentioned above, the<a>cube</a>root of Unity are 1,𝛚, 𝛚², where 1 is a real root, 𝛚 and 𝛚² are the imaginary roots. The essential features or properties of the cube root of Unity are:</p>
8
<p>The imaginary roots 𝛚 and 𝛚², when multiplied together, yields 1</p>
8
<p>The imaginary roots 𝛚 and 𝛚², when multiplied together, yields 1</p>
9
<p>𝛚×𝛚²= 𝛚³=1</p>
9
<p>𝛚×𝛚²= 𝛚³=1</p>
10
<p>The summation of the roots is zero → 1+𝛚+𝛚²=0.</p>
10
<p>The summation of the roots is zero → 1+𝛚+𝛚²=0.</p>
11
<p>The imaginary root 𝛚, when squared, is expressed as 𝛚², which is equal to another imaginary root.</p>
11
<p>The imaginary root 𝛚, when squared, is expressed as 𝛚², which is equal to another imaginary root.</p>
12
<p>Fact check: Do you know? The values of Cube root of (-1) are -1, -𝛚, and -𝛚² </p>
12
<p>Fact check: Do you know? The values of Cube root of (-1) are -1, -𝛚, and -𝛚² </p>
13
<h2>Finding the Cube Root of Unity</h2>
13
<h2>Finding the Cube Root of Unity</h2>
14
<p>Now, let us find the meaning of 𝛚 here. To find the<a>cube root</a>of Unity, we will make use of some algebraic<a>formulas</a>. We know that, the cube root of unity is represented as ∛1. Let us assume that ∛1= a so,</p>
14
<p>Now, let us find the meaning of 𝛚 here. To find the<a>cube root</a>of Unity, we will make use of some algebraic<a>formulas</a>. We know that, the cube root of unity is represented as ∛1. Let us assume that ∛1= a so,</p>
15
<p>∛1= a</p>
15
<p>∛1= a</p>
16
<p>⇒ 1 = a3</p>
16
<p>⇒ 1 = a3</p>
17
<p>⇒ a3- 1 = 0 </p>
17
<p>⇒ a3- 1 = 0 </p>
18
<p> ⇒ (a - 1)(a2+a+1) = 0 [using a3-b3= (a - b)(a2+a.b+b2)]</p>
18
<p> ⇒ (a - 1)(a2+a+1) = 0 [using a3-b3= (a - b)(a2+a.b+b2)]</p>
19
<p>⇒a - 1 =0</p>
19
<p>⇒a - 1 =0</p>
20
<p>⇒ a= 1 …………..(1) </p>
20
<p>⇒ a= 1 …………..(1) </p>
21
<p>Again, a2+a+1 = 0</p>
21
<p>Again, a2+a+1 = 0</p>
22
<p> ⇒ a = (-1 ±√(12-4×1×1)) / 2×1</p>
22
<p> ⇒ a = (-1 ±√(12-4×1×1)) / 2×1</p>
23
<p>⇒ a = (-1 ±√(-3)) / 2</p>
23
<p>⇒ a = (-1 ±√(-3)) / 2</p>
24
<p>⇒ a = (-1 ± i√3) / 2</p>
24
<p>⇒ a = (-1 ± i√3) / 2</p>
25
<p>⇒ a = (-1 + i√3) / 2 …………(2)</p>
25
<p>⇒ a = (-1 + i√3) / 2 …………(2)</p>
26
<p>Or</p>
26
<p>Or</p>
27
<p>a = (-1 - i√3) / 2 …………(3)</p>
27
<p>a = (-1 - i√3) / 2 …………(3)</p>
28
<p>From<a>equation</a>(1), (2), and (3), we get,</p>
28
<p>From<a>equation</a>(1), (2), and (3), we get,</p>
29
<p>The roots are → 1, (-1 + i√3) / 2 and (-1 - i√3) / 2</p>
29
<p>The roots are → 1, (-1 + i√3) / 2 and (-1 - i√3) / 2</p>
30
<p> Hence, 𝛚 = (-1 + i√3) / 2</p>
30
<p> Hence, 𝛚 = (-1 + i√3) / 2</p>
31
<p>𝛚2= (-1 - i√3) / 2 </p>
31
<p>𝛚2= (-1 - i√3) / 2 </p>
32
<h2>Common Mistakes and How to Avoid Them in the Cube Root of Unity</h2>
32
<h2>Common Mistakes and How to Avoid Them in the Cube Root of Unity</h2>
33
<p>some common mistakes with their solutions given:</p>
33
<p>some common mistakes with their solutions given:</p>
34
<h3>Explore Our Programs</h3>
34
<h3>Explore Our Programs</h3>
35
-
<p>No Courses Available</p>
35
+
<h2>Download Worksheets</h2>
36
<h3>Problem 1</h3>
36
<h3>Problem 1</h3>
37
<p>Factorize m²+ mn + n²</p>
37
<p>Factorize m²+ mn + n²</p>
38
<p>Okay, lets begin</p>
38
<p>Okay, lets begin</p>
39
<p>We know that, 1+𝛚+𝛚2=0</p>
39
<p>We know that, 1+𝛚+𝛚2=0</p>
40
<p>⇒ 𝛚+𝛚2= -1 ……….(1)</p>
40
<p>⇒ 𝛚+𝛚2= -1 ……….(1)</p>
41
<p>And, 𝛚3=1 …….(2)</p>
41
<p>And, 𝛚3=1 …….(2)</p>
42
<p>So, m2+mn+n2</p>
42
<p>So, m2+mn+n2</p>
43
<p>= m2 - (-1)mn +1× n2</p>
43
<p>= m2 - (-1)mn +1× n2</p>
44
<p>= m2 - (𝛚+𝛚2)mn + 𝛚3× n2 [Using (1) and (2)]</p>
44
<p>= m2 - (𝛚+𝛚2)mn + 𝛚3× n2 [Using (1) and (2)]</p>
45
<p>= m2- mn𝛚- mn𝛚2+ n2𝛚3</p>
45
<p>= m2- mn𝛚- mn𝛚2+ n2𝛚3</p>
46
<p>= m(m-n𝛚) -n𝛚2(m-n𝛚)</p>
46
<p>= m(m-n𝛚) -n𝛚2(m-n𝛚)</p>
47
<p>= (m-n𝛚)(m-n𝛚2)</p>
47
<p>= (m-n𝛚)(m-n𝛚2)</p>
48
<p>Answer : (m-n𝛚)(m-n𝛚2) </p>
48
<p>Answer : (m-n𝛚)(m-n𝛚2) </p>
49
<h3>Explanation</h3>
49
<h3>Explanation</h3>
50
<p>We used the properties of the cube root of unity to factorise the expression. </p>
50
<p>We used the properties of the cube root of unity to factorise the expression. </p>
51
<p>Well explained 👍</p>
51
<p>Well explained 👍</p>
52
<h3>Problem 2</h3>
52
<h3>Problem 2</h3>
53
<p>Find 𝛚⁶⁶</p>
53
<p>Find 𝛚⁶⁶</p>
54
<p>Okay, lets begin</p>
54
<p>Okay, lets begin</p>
55
<p>𝛚66</p>
55
<p>𝛚66</p>
56
<p>=(𝛚3)22</p>
56
<p>=(𝛚3)22</p>
57
<p>=(1)22</p>
57
<p>=(1)22</p>
58
<p>=1</p>
58
<p>=1</p>
59
<p>Answer: 1 </p>
59
<p>Answer: 1 </p>
60
<h3>Explanation</h3>
60
<h3>Explanation</h3>
61
<p>We used the property 𝛚3=1, and solved the expression. </p>
61
<p>We used the property 𝛚3=1, and solved the expression. </p>
62
<p>Well explained 👍</p>
62
<p>Well explained 👍</p>
63
<h3>Problem 3</h3>
63
<h3>Problem 3</h3>
64
<p>Prove that (1+𝛚)³+(1+𝛚²)³ = -2</p>
64
<p>Prove that (1+𝛚)³+(1+𝛚²)³ = -2</p>
65
<p>Okay, lets begin</p>
65
<p>Okay, lets begin</p>
66
<p>We know that, 1+𝛚+𝛚2=0 ⇒1+𝛚= -𝛚2 ……….(1) And also, 1+𝛚2= -𝛚 ………(2)</p>
66
<p>We know that, 1+𝛚+𝛚2=0 ⇒1+𝛚= -𝛚2 ……….(1) And also, 1+𝛚2= -𝛚 ………(2)</p>
67
<p> LHS = (1+𝛚)3+(1+𝛚2)3</p>
67
<p> LHS = (1+𝛚)3+(1+𝛚2)3</p>
68
<p>=(-𝛚2)3+(-𝛚)3 [Using (1) and (2)]</p>
68
<p>=(-𝛚2)3+(-𝛚)3 [Using (1) and (2)]</p>
69
<p>=(-𝛚6)+(-𝛚3) </p>
69
<p>=(-𝛚6)+(-𝛚3) </p>
70
<p>= -(𝛚3)2 - (𝛚3)</p>
70
<p>= -(𝛚3)2 - (𝛚3)</p>
71
<p>=-(1)2 - 1 [using the property 𝛚3=1]</p>
71
<p>=-(1)2 - 1 [using the property 𝛚3=1]</p>
72
<p>= -1-1</p>
72
<p>= -1-1</p>
73
<p>=-2</p>
73
<p>=-2</p>
74
<p>=RHS [proved] </p>
74
<p>=RHS [proved] </p>
75
<h3>Explanation</h3>
75
<h3>Explanation</h3>
76
<p>We proved the given expression to be true using properties of cube root if unity like 1+𝛚+𝛚2=0 and 𝛚3=1. </p>
76
<p>We proved the given expression to be true using properties of cube root if unity like 1+𝛚+𝛚2=0 and 𝛚3=1. </p>
77
<p>Well explained 👍</p>
77
<p>Well explained 👍</p>
78
<h3>Problem 4</h3>
78
<h3>Problem 4</h3>
79
<p>Prove that (1+𝛚-𝛚²)⁶= -64</p>
79
<p>Prove that (1+𝛚-𝛚²)⁶= -64</p>
80
<p>Okay, lets begin</p>
80
<p>Okay, lets begin</p>
81
<p>We know that, 1+𝛚+𝛚2=0</p>
81
<p>We know that, 1+𝛚+𝛚2=0</p>
82
<p> ⇒1+ 𝛚= -𝛚2 ……….(1)</p>
82
<p> ⇒1+ 𝛚= -𝛚2 ……….(1)</p>
83
<p>And, 𝛚3=1 …….(2)</p>
83
<p>And, 𝛚3=1 …….(2)</p>
84
<p>LHS</p>
84
<p>LHS</p>
85
<p>= (1+𝛚-𝛚2)6</p>
85
<p>= (1+𝛚-𝛚2)6</p>
86
<p>=(-𝛚2-𝛚2)6 [using (1)]</p>
86
<p>=(-𝛚2-𝛚2)6 [using (1)]</p>
87
<p>=(-2𝛚2)6</p>
87
<p>=(-2𝛚2)6</p>
88
<p>=26 × (-𝛚2)6</p>
88
<p>=26 × (-𝛚2)6</p>
89
<p>=64× (-𝛚12)</p>
89
<p>=64× (-𝛚12)</p>
90
<p>= 64× (-(𝛚3)4)</p>
90
<p>= 64× (-(𝛚3)4)</p>
91
<p>= 64× (-(1)4)</p>
91
<p>= 64× (-(1)4)</p>
92
<p>= 64× (-1)</p>
92
<p>= 64× (-1)</p>
93
<p>= -64</p>
93
<p>= -64</p>
94
<p>=RHS </p>
94
<p>=RHS </p>
95
<h3>Explanation</h3>
95
<h3>Explanation</h3>
96
<p>LHS=RHS</p>
96
<p>LHS=RHS</p>
97
<p>Hence proved</p>
97
<p>Hence proved</p>
98
<p>Well explained 👍</p>
98
<p>Well explained 👍</p>
99
<h2>FAQs for Cube Root of Unity</h2>
99
<h2>FAQs for Cube Root of Unity</h2>
100
<h3>1.What is the cube root of unity rule?</h3>
100
<h3>1.What is the cube root of unity rule?</h3>
101
<p> The cube root of unity has three roots → 1,𝛚, and 𝛚2, 1 is the real root, and 𝛚 and 𝛚2 are the imaginary roots. Also, the important properties of cube root of unity include: </p>
101
<p> The cube root of unity has three roots → 1,𝛚, and 𝛚2, 1 is the real root, and 𝛚 and 𝛚2 are the imaginary roots. Also, the important properties of cube root of unity include: </p>
102
<p>1+𝛚+𝛚2=0</p>
102
<p>1+𝛚+𝛚2=0</p>
103
<p>𝛚3=1</p>
103
<p>𝛚3=1</p>
104
<p>The<a>square</a>of the imaginary root omega, 𝛚 is the other imaginary root, 𝛚2 </p>
104
<p>The<a>square</a>of the imaginary root omega, 𝛚 is the other imaginary root, 𝛚2 </p>
105
<h3>2.What is the expression of the cube root of unity ?</h3>
105
<h3>2.What is the expression of the cube root of unity ?</h3>
106
<p>The<a>expression</a>of cube root of unity is x3=1 or, x=∛1. We generally solve this expression by using the formula a3-b3= (a - b)(a2+a.b+b2). </p>
106
<p>The<a>expression</a>of cube root of unity is x3=1 or, x=∛1. We generally solve this expression by using the formula a3-b3= (a - b)(a2+a.b+b2). </p>
107
<h3>3.How do you find the cube root of unity?</h3>
107
<h3>3.How do you find the cube root of unity?</h3>
108
<p>We can find the cube root of unity, i.e., the values of 𝛚 and 𝛚2 by solving the expression x3=1 or, x=∛1, using the formula a3-b3= (a - b)(a2+a.b+b2). We then land on to a value which deals with the Complex<a>numbers</a></p>
108
<p>We can find the cube root of unity, i.e., the values of 𝛚 and 𝛚2 by solving the expression x3=1 or, x=∛1, using the formula a3-b3= (a - b)(a2+a.b+b2). We then land on to a value which deals with the Complex<a>numbers</a></p>
109
<h3>4. Is the cube root of unity 1?</h3>
109
<h3>4. Is the cube root of unity 1?</h3>
110
<p>The cube root of unity is not only 1, it comprises two imaginary roots also, </p>
110
<p>The cube root of unity is not only 1, it comprises two imaginary roots also, </p>
111
<p>𝛚 = (-1 + i√3) / 2 and 𝛚2= (-1 - i√3) / 2. </p>
111
<p>𝛚 = (-1 + i√3) / 2 and 𝛚2= (-1 - i√3) / 2. </p>
112
<h2>Important Glossaries for Cube Root of Unity</h2>
112
<h2>Important Glossaries for Cube Root of Unity</h2>
113
<ul><li><strong>Omega -</strong>This is a symbol used for depicting the imaginary roots of the cube root of unity. It is represented by 𝛚. </li>
113
<ul><li><strong>Omega -</strong>This is a symbol used for depicting the imaginary roots of the cube root of unity. It is represented by 𝛚. </li>
114
</ul><ul><li><strong>Complex Number -</strong>The numbers which are represented as m+i.n, where m and n are real numbers and “i”, known as iota, is an imaginary number. </li>
114
</ul><ul><li><strong>Complex Number -</strong>The numbers which are represented as m+i.n, where m and n are real numbers and “i”, known as iota, is an imaginary number. </li>
115
</ul><h2>Jaskaran Singh Saluja</h2>
115
</ul><h2>Jaskaran Singh Saluja</h2>
116
<h3>About the Author</h3>
116
<h3>About the Author</h3>
117
<p>Jaskaran Singh Saluja is a math wizard with nearly three years of experience as a math teacher. His expertise is in algebra, so he can make algebra classes interesting by turning tricky equations into simple puzzles.</p>
117
<p>Jaskaran Singh Saluja is a math wizard with nearly three years of experience as a math teacher. His expertise is in algebra, so he can make algebra classes interesting by turning tricky equations into simple puzzles.</p>
118
<h3>Fun Fact</h3>
118
<h3>Fun Fact</h3>
119
<p>: He loves to play the quiz with kids through algebra to make kids love it.</p>
119
<p>: He loves to play the quiz with kids through algebra to make kids love it.</p>