Rivalry2

HTML Diff

2 added 2 removed

Original 2026-01-01

Modified 2026-02-28

1 - <p>473 Learners</p>

1 + <p>565 Learners</p>

2 <p>Last updated on<strong>August 5, 2025</strong></p>

3 <p>Square root is simply a number value that when multiplied with itself gives the original number. We apply square roots when we make financial estimations and solve practical problems in geometry.</p>

4 <h2>What is the square root of 38?</h2>

5 <p>The<a>square</a>root is the<a>number</a>that gives the original number when squared. </p>

6 <p>√38 = 6.16441400297 in<a>exponential form</a>it is written as√38 =381/2.</p>

7 <p>In this article we will learn more about the square root<a>of</a>38, how to find it and common mistakes one may make when trying to find the square root. </p>

8 <h2>Finding the square root of 38</h2>

9 <p>To find the<a>square root</a>of a number students learn many different methods. When a number is a<a>perfect square</a>and the process of finding square root is simple. </p>

10 <h3>Square root of 38 using the prime factorization method</h3>

11 <p>Breakdown 38 into<a>prime factors</a>, group them and the result is the square root. </p>

12 <p>Prime factorization of 38; </p>

13 <p>38= 2×19</p>

14 <p>All prime factors cannot form pairs. We cannot simplify this further. Hence, the square root of 38 cannot be expressed in simple radical form.√38 is irrational. </p>

15 <h3>Explore Our Programs</h3>

16 - <p>No Courses Available</p>

17 <h3>Square root of 38 using the division method</h3>

16 <h3>Square root of 38 using the division method</h3>

18 <p>Pair the digits, begin with the largest square and continue the<a>subtraction</a>and<a>division</a>till we find the result which is the square root of the number. </p>

17 <p>Pair the digits, begin with the largest square and continue the<a>subtraction</a>and<a>division</a>till we find the result which is the square root of the number. </p>

19 <p><strong>Step 1:</strong>Pair 38 with zeros as it has no<a>decimals</a>in it.</p>

18 <p><strong>Step 1:</strong>Pair 38 with zeros as it has no<a>decimals</a>in it.</p>

20 <p>38.00→ (38)(00) </p>

19 <p>38.00→ (38)(00) </p>

21 <p><strong>Step 2:</strong>pick a number whose square is ≤ 38, 62=36</p>

20 <p><strong>Step 2:</strong>pick a number whose square is ≤ 38, 62=36</p>

22 <p>- 6 is the<a>quotient</a>. </p>

21 <p>- 6 is the<a>quotient</a>. </p>

23 <p>- Subtract the numbers, 38-36=2. </p>

22 <p>- Subtract the numbers, 38-36=2. </p>

24 <p>- Bring down the numbers next to the<a>remainder</a>.</p>

23 <p>- Bring down the numbers next to the<a>remainder</a>.</p>

25 <p><strong>Step 3:</strong>double quotient and use it as the first digit of the new<a>divisor</a>’s</p>

24 <p><strong>Step 3:</strong>double quotient and use it as the first digit of the new<a>divisor</a>’s</p>

26 <p>- Double 6</p>

25 <p>- Double 6</p>

27 <p>- Now find the digit x in a way that 2x×x ≤ 200</p>

26 <p>- Now find the digit x in a way that 2x×x ≤ 200</p>

28 <p>- x is 1, 121×1 = 121.</p>

27 <p>- x is 1, 121×1 = 121.</p>

29 <p><strong>Step 4:</strong>Now find the final quotient </p>

28 <p><strong>Step 4:</strong>Now find the final quotient </p>

30 <p>The result; √38 = 6.16441</p>

29 <p>The result; √38 = 6.16441</p>

31 <h3>Square root of 38 using the approximation method</h3>

30 <h3>Square root of 38 using the approximation method</h3>

32 <p>In the approximation method, we estimate the square root by considering the closest perfect square to 38. </p>

31 <p>In the approximation method, we estimate the square root by considering the closest perfect square to 38. </p>

33 <p>Follow the below steps; </p>

32 <p>Follow the below steps; </p>

34 <p><strong>Step 1:</strong>Nearest perfect square to 38 → √36=6 and √49 = 7 </p>

33 <p><strong>Step 1:</strong>Nearest perfect square to 38 → √36=6 and √49 = 7 </p>

35 <p><strong>Step 2:</strong>38 falls between 36 and 49 therefore the square root falls between 6 and 7</p>

34 <p><strong>Step 2:</strong>38 falls between 36 and 49 therefore the square root falls between 6 and 7</p>

36 <p><strong>Step 3:</strong>We try to test numbers like 6.1,6.08 and further. We find that √38 = 6.16441. </p>

35 <p><strong>Step 3:</strong>We try to test numbers like 6.1,6.08 and further. We find that √38 = 6.16441. </p>

37 <h2>Common Mistakes and How to Avoid Them in the Square Root of 38</h2>

36 <h2>Common Mistakes and How to Avoid Them in the Square Root of 38</h2>

38 <p>Students make errors when learning to find the square root of a number. Here are errors and tips to avoid them. </p>

37 <p>Students make errors when learning to find the square root of a number. Here are errors and tips to avoid them. </p>

38 + <h2>Download Worksheets</h2>

39 <h3>Problem 1</h3>

40 <p>Simplify 4√38+5√38.Combine the terms and simplify the expression.</p>

41 <p>Okay, lets begin</p>

42 <p>Both terms have √38 as a common factor, so factor it out: </p>

43 <p>4√38+5√38=√38(4+5)=9√38 </p>

44 <h3>Explanation</h3>

45 <p>The terms are combined by factoring out the common √38, simplifying to 9√38. </p>

46 <p>Well explained 👍</p>

47 <h3>Problem 2</h3>

48 <p>If y=√38 , find y³+2y²</p>

49 <p>Okay, lets begin</p>

50 <p>Approximate y≈6.16, then compute each term: </p>

51 <p>y2≈(6.16)2=38, y3≈(6.16)3=234.8</p>

52 <p>Now compute y3+2y2: </p>

53 <p>y3+2y2≈234.85+2(38)2=234.85+76=310.85 </p>

54 <h3>Explanation</h3>

55 <p>By approximating y, we calculate y3+2y2 step by step to get an approximate result. </p>

56 <p>Well explained 👍</p>

57 <h3>Problem 3</h3>

58 <p>You are tasked with designing a square garden whose area is 38 m². You want to place a fence around the garden and need to calculate the perimeter of the garden. However, you can only use approximate methods for non-perfect square roots.</p>

59 <p>Okay, lets begin</p>

60 <p>1. Finding the square root of 38</p>

61 <p>- The two closest perfect squares to 38 are 36 (√36 = 6) and 49 (√49 = 7).</p>

62 <p>- Using approximation methods like trial and error, we estimate:</p>

63 <p>√38≈6.16</p>

64 <p>(Exact calculation yields √38 ≈ 6.164).</p>

65 <p>2. Calculating the perimeter of a square is given by:</p>

66 <p>P=4×side length</p>

67 <p>Substituting the approximate side length of the garden:</p>

68 <p>P≈4×6.16=24.64 </p>

69 <p>Answer: The perimeter of the garden is approximately 24.64 meters. </p>

70 <h3>Explanation</h3>

71 <p>By taking the square root of the area, we find the side length. Applying the perimeter formula, we get the solution. </p>

72 <p>Well explained 👍</p>

73 <h2>FAQs on the Square root of 38</h2>

74 <h3>1.What is the square of 38?</h3>

75 <p>-Multiplying 38 with 38 is how we find the square of a number, 1444 is the square of 38. </p>

76 <h3>2.What is the value of √37?</h3>

77 <p>- When we simplify for √37, break the number down to<a>factors</a>that include a perfect square. By approximation, we get 6.0827. </p>

78 <h3>3.Is 70 a perfect square?</h3>

79 <p>-70 is not a perfect square. Perfect square is a number that we get after squaring an<a>integer</a>. </p>

80 <h3>4. Is 45 a perfect square?</h3>

81 <p>- 45 is not a perfect square. Perfect square is a number that we get after squaring an integer. </p>

82 <h3>5. What is √66?</h3>

83 <p>-When we simplify for √66, break the number down to factors that include a perfect square. By approximating, we get 8.124. </p>

84 <h2>Important glossaries for the square root of 38</h2>

85 <ul><li><strong>Prime numbers</strong>- a number whose factors are itself and 1 </li>

86 </ul><ul><li><strong>Integer</strong>- A number between zero and infinite, that can be in any form; positive or negative, whole or decimal</li>

87 </ul><ul><li><strong>Perfect square number</strong>- any number with non decimals in its square root </li>

88 </ul><ul><li><strong>Non-perfect square numbers</strong>- A number whose square is represented as a fraction or decimal in its result. </li>

89 </ul><p>What Is Algebra? 🧮 | Simple Explanation with 🎯 Cool Examples for Kids | ✨BrightCHAMPS Math</p>

90 <p>▶</p>