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Original 2026-01-01
Modified 2026-02-28
1 <p>We can derive the derivative of x²/2 using proofs.</p>
1 <p>We can derive the derivative of x²/2 using proofs.</p>
2 <p>To show this, we will use the rules of differentiation.</p>
2 <p>To show this, we will use the rules of differentiation.</p>
3 <p>There are several methods we use to prove this, such as:</p>
3 <p>There are several methods we use to prove this, such as:</p>
4 <p>By First Principle</p>
4 <p>By First Principle</p>
5 <p>Using Power Rule</p>
5 <p>Using Power Rule</p>
6 <p>Using Constant Multiple Rule</p>
6 <p>Using Constant Multiple Rule</p>
7 <p>We will now demonstrate that the differentiation of x²/2 results in x using the above-mentioned methods:</p>
7 <p>We will now demonstrate that the differentiation of x²/2 results in x using the above-mentioned methods:</p>
8 <p>By First Principle</p>
8 <p>By First Principle</p>
9 <p>The derivative of x²/2 can be proved using the First Principle, which expresses the derivative as the limit of the difference<a>quotient</a>.</p>
9 <p>The derivative of x²/2 can be proved using the First Principle, which expresses the derivative as the limit of the difference<a>quotient</a>.</p>
10 <p>To find the derivative of x²/2 using the first principle, we will consider f(x) = x²/2.</p>
10 <p>To find the derivative of x²/2 using the first principle, we will consider f(x) = x²/2.</p>
11 <p>Its derivative can be expressed as the following limit. f'(x) = limₕ→₀ [f(x + h) - f(x)] / h … (1)</p>
11 <p>Its derivative can be expressed as the following limit. f'(x) = limₕ→₀ [f(x + h) - f(x)] / h … (1)</p>
12 <p>Given that f(x) = x²/2, we write f(x + h) = (x + h)²/2.</p>
12 <p>Given that f(x) = x²/2, we write f(x + h) = (x + h)²/2.</p>
13 <p>Substituting these into<a>equation</a>(1), f'(x) = limₕ→₀ [(x + h)²/2 - x²/2] / h = limₕ→₀ [(x² + 2xh + h²)/2 - x²/2] / h = limₕ→₀ [2xh + h²]/2h = limₕ→₀ [x + h/2] As h approaches 0, f'(x) = x.</p>
13 <p>Substituting these into<a>equation</a>(1), f'(x) = limₕ→₀ [(x + h)²/2 - x²/2] / h = limₕ→₀ [(x² + 2xh + h²)/2 - x²/2] / h = limₕ→₀ [2xh + h²]/2h = limₕ→₀ [x + h/2] As h approaches 0, f'(x) = x.</p>
14 <p>Hence, proved.</p>
14 <p>Hence, proved.</p>
15 <p>Using Power Rule</p>
15 <p>Using Power Rule</p>
16 <p>To prove the differentiation of x²/2 using the<a>power</a>rule, We use the formula: d/dx (xⁿ) = n*xⁿ⁻¹</p>
16 <p>To prove the differentiation of x²/2 using the<a>power</a>rule, We use the formula: d/dx (xⁿ) = n*xⁿ⁻¹</p>
17 <p>For x², n = 2.</p>
17 <p>For x², n = 2.</p>
18 <p>So, d/dx (x²) = 2*x¹ = 2x. Since we have x²/2, d/dx (x²/2) = (1/2)*d/dx (x²) = (1/2)*2x = x.</p>
18 <p>So, d/dx (x²) = 2*x¹ = 2x. Since we have x²/2, d/dx (x²/2) = (1/2)*d/dx (x²) = (1/2)*2x = x.</p>
19 <p>Using Constant Multiple Rule</p>
19 <p>Using Constant Multiple Rule</p>
20 <p>We will now prove the derivative of x²/2 using the constant<a>multiple</a>rule.</p>
20 <p>We will now prove the derivative of x²/2 using the constant<a>multiple</a>rule.</p>
21 <p>The formula we use is: d/dx (c*f(x)) = c*d/dx (f(x))</p>
21 <p>The formula we use is: d/dx (c*f(x)) = c*d/dx (f(x))</p>
22 <p>Let c = 1/2 and f(x) = x².</p>
22 <p>Let c = 1/2 and f(x) = x².</p>
23 <p>So, d/dx (x²/2) = (1/2)*d/dx (x²) = (1/2)*2x = x.</p>
23 <p>So, d/dx (x²/2) = (1/2)*d/dx (x²) = (1/2)*2x = x.</p>
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